how do yuo do this math problem?

Question

2+(6m+3)7

Answer 1

You need to use the distributive property and multiply everything out, then combine. (Just like the last one I showed you how to do!)

2 + (6m+3)7 =

2 + 6m(7) + 3(7) =

2 + 42m + 21 =

42m + 23

~~~~~~~~~~

The way you've written this problem and your other one seem really odd. Maybe math problems have changed in the 30 decades since I was in grade school, but in my day a problem would not have been written like this. Are you sure you're writing your HW problems down correctly?

Answer 2

First, begin with the parentheses. (6m+3). Add the equivalent number of 6m (for example, if m was 6, 6m would be 36) to 3 (39). Now, multiply by 7 (the seven outside the group of parentheses.
39
x 7
____
273
Now, just add two to the product. 273 + 2=279! (Only if m is six.)

The best way to use my method is memorizing this sentence:

Please Excuse My Dear Aunt Sally
a x u i d u
r p l v d b
e o t i i t
n n . s t .
t e i i
h n o o
e t n n
s
e
s
Use this sentence in chronological order: parentheses first, then exponents, multiplication, division, addition, subtraction.
Also, please note that multiplication and division are interchangeable, and that addition and subtraction are interchangeable.

Answer 3

If the directions say "simplify", you'd distribute the 7 times the numbers in parentheses and get 2 + 42m + 21. Then you'd combine the like terms and get 23 + 42m.

Answer 4

this is how u work the problem ou


2+(6m+3)7
2+42m+21
42m+23 is ur answer

Answer 5

be careful with this question, because you use distributive property in it.
remember to multiply the7 by 6m+3
2+42m+21
42m+23
42m+23 is the final answer

Answer 6

follow the order of operations...do multiplication before adding...becomes 2 + (42m + 21) no nee for () with addition so becomes 2 + 42m + 21 which equals 23 + 42 m

Answer 7

first multiply the 7 by each factor inside the brackets
this gives you 2+ 42m + 21
then simplify by combining like terms giving the final answer of
42m + 23

Answer 8

I would do it by posting on Yahoo Answers.