2(x+3)+3(X+4)
Step 1---distribute
2X+6+3X+62=73
Step 2--combine like terms
5X+18=73
Step 3--Divide 73 by 5 to leave X by itself
X=11
Step 4--plug it in the original equation
2(11+3)+3(11+4)=73 where X=11
28+45=73
73=73 it checks
JUST remember to distribute and be careful...remember once you find what X is you can always plus it in to the original equation to check whether or not your answer is correct. This is how i got As on both Algebra 1, Algebra 2 and Precalculus...trust me...this stuff is easy you just gotta put like 2hrs everyday though so no more TV!!! hahahah
Good luck kid ;)
2006-10-09 12:58:18
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answer #1
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answered by christiansareawesome 4
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Simple!
First, distribute the 2 over the (x=3) in the equation, next the 3 over the (x+4)
(If you don't know what I mean, 2(x+3) is the same as 2*x+2*3, so that would come out as 2x+6. Do the same thing for 3(x+4)
Now, your equation should look like
2x+6+3x+12=73
Combine Like Terms (add the 2x and 3x together, add the 6 and the 12 together) to get
5x+18=73.
Now subtract 18 from both sides to isolate the variable (meaning to get the 5x all by itself) You should have
5x=55
Now divide both sides by 5 to get x in its simplest form (not being multiplied or divided by anything.) You'll have
x=11
Good Luck on the rest of your homework. I hope I was helpful!!
2006-10-09 13:02:50
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answer #2
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answered by Lee 3
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2(x+3)+3(x+4)=73
distribute the 2 and the 3
2x+6+3x+12=73
add the 2 and the 3 and add the 6 and the 12
5x+18=73
subtract the 18 by 18 and the 73 by 18
18-18=0
and
73-18=55
divide the 55 by the 5
55/5x=11
and the answer is x=11
I hope this helps you good luck!
2006-10-09 13:05:14
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answer #3
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answered by I'm learning. 2
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i mite no this k.. lets see... 2(x+3)+3(x+4)=73
u add all the x's and #'s 2x+6+3x+12=73
minus 18 from both sides 5x+18=73
-18=-18
then u divide the 5 5x=55
x=11
2006-10-09 13:02:50
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answer #4
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answered by ~$LiL$*RiNa*~ 1
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I think you should be able to do this
remove ()'s 2x+6 + 3x+12 = 73 (I think 73)
5x + 18 = 73
5X = 73 - 18 = 55
X = 55/5 = 11
COME ON NOW you didn't need help
2006-10-09 13:03:15
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answer #5
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answered by rwbblb46 4
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11
2006-10-09 12:58:25
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answer #6
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answered by cubsfan90 2
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Sure..
First distribute, then you get
2x +6 + 3x +12 = 73
Then you combine like terms (add all the x's with each other and the regular numbers with each other), then you get
5x +18 = 73
Then you want the number with the x alone on one side of the equal sign. In order to do that, subtract 18 from both sides of the equal sign so you get 0 on the left, giving you
5x = 55
Then you want the x to be completely alone. To do that divide this time on both sides by 5 so that there will be a 1 in front of the x. You dont want to subtract by 5 this time, because 5x means 5 times x. Dividing both sides gives you
x = 11
and thats your answer
2006-10-09 13:00:54
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answer #7
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answered by DtotheC 1
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2(x+3) + 3(x+4)=73/
2x+6+3x+12=73
5x+18=73
x=11
2006-10-09 12:59:57
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answer #8
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answered by amandaangel1 2
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x=3
2006-10-09 12:57:52
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answer #9
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answered by www.mrcooldude.com 2
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x=11
2006-10-09 12:59:10
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answer #10
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answered by the soccer guy 3
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