algebra 2 confusion!?

Question

alright, i have this problem

4[x-(3+2x)] + 5 = 3(x+11)
when i solved it.. i got
4[x-3+2x]+5
4x-12+8x+5
answer 12x - 7 <<< is that right??
because later i have choices..which one is it??

a) 31/3 b) 40/9 c) 2 d) 5

what i do wrong??

Answer 1

4[x-(3+2x)] + 5 = 3(x+11)
4[x-3-2x] + 5 = 3x + 33
4x - 12 - 8x + 5 = 3x + 33
-4x - 7 = 3x + 33
-7 - 33 = 3x + 4x
-40 = 7x
x = -40/7

I think your problem is that when you do the -(-3 + 2x), the "-" also applies to 2x. Instead of having +2x, you should have -2x.

I am sorry, I didn't get the answer as one of your a), b), c) or d). Please make sure if you have copied the correct question.

Answer 2

First off, you need to distribute the negative sign by the parentheses. 4[x - (3 + 2x)] + 5 simplifies to 4[x - 3 - 2x] + 5, which would in turn simplify to 4x - 12 - 8x + 5 or -4x - 7.

You then need to simplify the other side of the equation and solve it.

Answer 3

Your mistake is that you forgot to make something negative instead of positive. Observe:

4[X-(3+2X)]+5=3(X+11)
4[X-3-2x]+5=3x+33
4X-12-8x+5=3x+33
-4X-7=3X+33
-7X=40
7X= -40
X= -40/7

Answer 4

4[x-3-2x]+5=3x+33
-4x-12+5=3x+33
-7x=40
x=-40/7
either you have copied the sum wrong or youranswer choices are wrong
if the sum reads
4[x-(3-2x]+5=3(x+11)
then your answer will be x=40/9
check up where you have made the mistake

Answer 5

4[x-(3+2x)] + 5 = 3(x+11)
4[x-3-2x]+5=3x+33
4x-12-8x+5=3x+33
4x-3x-8x=33+12-5
-7x=40
x=-40/7

This is the solution to this problem.

Answer 6

Go to www.allexperts.com, and look up the correct category. You'll find an answer there from a math expert. It's free!

Answer 7

R u supposed 2 find out what "x" is? -or- do u already know the value of "x"?

Answer 8

just put your equation and click solve
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=equations&s2=solve&s3=basic