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28+(97-3(to the 4th power))-5x7=

5(to the 3rd power)-84divided by12-(6x3)=

67+6(to the 2nd power)x6divided by (2+1)=

i dont remember how the powers work. any suggestions..Please help.. someone out there has to be smart..

2006-10-09 12:33:46 · 8 answers · asked by Nikkib 4 in Science & Mathematics Mathematics

8 answers

powers work like this: 3 to the 4th power (written as 3^4) is the same as 3 times 3 times 3 times 3, or in other words, 3 times itself 4 times.

28 + (97 - 3^4) - 5 * 7 = 28 + (97 - 81) - 35
= 44 - 35
= 9

5^3 - 84 / 12 - 6 * 3
(remember to do multiplication and division before any addition or subtraction unless accompanied by parentheses.)
= 5^3 - 7 - 18
= 125 - 25
= 100

67 + 6^2 * 6 / (2+1) = 67 + 36 * 6 / 3
= 67 + 216 / 3
= 67 + 72
= 139

2006-10-09 12:42:25 · answer #1 · answered by Anonymous · 0 0

28 + (97-81) -5x7= 28+16 -35 = 44-35= 9

125-7-18= 125-25= 100

67+36(6)/3= 67+72= 139

2006-10-09 19:36:57 · answer #2 · answered by Greg G 5 · 0 0

3 to the 4th power means 3X3X3X3 which is 81.

Then 97 - 81 is 16. Then you must do multiplication: 5x7 = 35

Finally 28 + 16 - 35 is 9

2006-10-09 19:38:12 · answer #3 · answered by hayharbr 7 · 0 0

In general, if exponents give you trouble, write the bloody things out.

28 + (97 - (3*3*3*3)) - 5*7

(5*5*5) - 84/12 - 6*3

67 + (6*6)*6/(2+1)

You know how to multiply, so you should be able to do these problems just fine. :-)

If you grind through the math, the answers are 9, 100, and 139, as shown by the first responder.

2006-10-09 19:40:45 · answer #4 · answered by Bramblyspam 7 · 0 0

28+16-35=9

2. 125-7-18=100

3. 67+72=139

2006-10-09 19:40:50 · answer #5 · answered by raj 7 · 0 0

problem 1

28+(16)-5*7
28+(16)-35=9

Problem 2

125-84/12-(6*3)
125-7-(6*3)
125-7-18=100

problem 3
103 * 6/(2+1)
103*2=206

hope it helps

2006-10-09 19:41:00 · answer #6 · answered by Anonymous · 0 0

5 to the third power is 5x5x5

2006-10-09 19:38:56 · answer #7 · answered by Anonymous · 0 0

the first one is 112
2.=11
3=76

2006-10-09 19:51:11 · answer #8 · answered by Jasmine S 1 · 0 0

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