Just don't panic. Think about it. The number of adults (a) and children (c) is (=) 108. Right?
a + c = 108
and, there are five times as many children (c) as adults (a).
So c = 5 times a
c = 5a.
2006-10-09 11:17:54
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answer #1
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answered by All hat 7
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No Problem! You know that the total number of people is 108. So just set up your variables. The number of childern is 5 x's more than the number of adults, so let adults = a and childern = c. However, childern equal 5 x's the number of adults so, childern actuall equall 5a.
Now your equation is:
5a + a = 108
-combine the a's
6a=108
- divide by 6 to get "a" alone
a=18
- Thus, adults (a) = 18 and childern(c or 5a) = 90
2006-10-09 18:22:48
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answer #2
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answered by Collegebound... I hope! 1
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You know that 108 people attended the game, so a + c = 108. You also know that there are five times as many children as adults, so c = 5a. That is your system. When you substitute for c in the first equation, the solution is basic algebra.
2006-10-09 18:15:13
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answer #3
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answered by DavidK93 7
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108 = c + a. If c = 5a (children is 5 time of adult) then
108 = 5a + a (replacing c for a here!!)
108 = 6a;
so a = 108/6 which is 18 (i.e 18 adults)
If we go back to the top equation
108 = c + a
c = 108 - a (re-arranging equation)
so c = 108 - 18 which 90 (i.e 90 children).
90 is also 5 times of 18. Bingo!!
Hope this help!
Soi
2006-10-09 18:47:17
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answer #4
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answered by soi d 1
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108 people total means a+c=108.
five times as many children as adults means c=5a.
2006-10-09 18:15:04
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answer #5
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answered by James L 5
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First you divide 108 people by 6. Then you get 18. In the end you get 18 adults and 90 children.
DON'T QUESTION IT!!!!
2006-10-09 18:29:38
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answer #6
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answered by Shaun B 2
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5a = c
5a + c = 108
2006-10-09 18:21:36
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answer #7
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answered by soulguy85 6
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Use Your Brain!
c number of children
a number of adults
c + a =108
c=5a
then you can solve
2006-10-09 18:18:13
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answer #8
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answered by rwbblb46 4
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5c + a = 108
a = 5c
2006-10-09 18:15:47
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answer #9
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answered by JennyAnn 4
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now I have a headache?
2006-10-09 18:14:29
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answer #10
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answered by Anonymous
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