2006-10-09 11:08:56 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The electrons will be mostly around the fluorine ion because fluorine is much more electronegative. Electronegative atoms and ions pull electrons towards them in bonds
2006-10-09 11:10:33 · answer #1 · answered by Greg G 5 · 1⤊ 0⤋
On the Fluorine since it has a higher electronegativity than the Hydrogen.. Fluorine needs to gain an electron in order to be stable.. Hydrogen can lose an electron to be stable... Good luck.
2006-10-09 11:11:33 · answer #2 · answered by KIm Z 3 · 0⤊ 0⤋
Fluorine is actually the most electronegative element on the periodic table of elements
2006-10-09 11:30:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Actually, H-F is a hydrogen bond. These bonds form when "H" binds with either "F, O, or N". These bonds usually form due to the high Electronegitivity and small atomic radius of the elements. Thus, between "H" and "F" the electrons will be attracted more to "F" than to "H". Also, electonegativity is just refers to an atoms ability to attract electrons.
2006-10-09 11:15:33 · answer #4 · answered by Collegebound... I hope! 1 · 0⤊ 0⤋
Around F. Fluorine is more electronegative and attracts electrons.
2006-10-09 11:13:01 · answer #5 · answered by beauty_fan 2 · 0⤊ 0⤋
Fluorine....since the fluorine atom has nine protons...and little shielding for outer electrons...they will tend to be attracted to the higher concentration of positive potential of the nucleus.
2006-10-09 11:12:37 · answer #6 · answered by Anonymous · 0⤊ 0⤋
fluorine, most electronegative element.
2006-10-09 11:46:26 · answer #7 · answered by Dr. J. 6 · 0⤊ 0⤋
F, it is more electronegative.
2006-10-09 11:10:26 · answer #8 · answered by treseuropean 6 · 1⤊ 0⤋