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what is the inverse function of sin(2/t)???

2006-10-09 10:23:54 · 6 answers · asked by ? 1 in Science & Mathematics Mathematics

6 answers

well dear Aditya;

The Inverse Trigonometric Functions are meant to be the `inverses' of the standard trigonometric functions.The inverse functions of sin, cos and tan are called arc sin, arc cos and arc tan. The notations sin^-1(x), cos^-1(x) and tan^-1(x) are also common, though they tend to be confusing to beginners.arc sin(x) is the angle whose sine is x ...if y = sin x then x = arc sin y. arc sin(x) is the angle between - and whose sine is x . ( -1 ≤ x ≤ +1)

Good Luck sweetheart.

2006-10-09 11:15:07 · answer #1 · answered by sweetie 5 · 6 0

y = sin(2/t) is original function. Switch y and t, then rearrange to find inverse:

t = sin(2/y)
arcsin (t) = arcsin (sin (2/y))
arcsin (t) = 2/y
y = 2 / arcsin(t)
is inverse.

2006-10-09 11:50:37 · answer #2 · answered by Joe C 3 · 0 0

y = sen(2/t)

2/t = arcsen y
2 = t arcseny
t= 2/arcset y

Now you exchange y and t


So: y = 2 / arcsent (t) is the inverse function


Ana

2006-10-10 15:21:55 · answer #3 · answered by Ilusion 4 · 0 0

1/sin(2/t)

2006-10-09 10:25:17 · answer #4 · answered by stop12345now 2 · 0 2

arcsin(t/2)


Doug

2006-10-09 10:27:43 · answer #5 · answered by doug_donaghue 7 · 1 1

give the t value
i wll give you the answer

2006-10-09 10:26:09 · answer #6 · answered by Show Me Sunshine 2 · 0 2

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