350.0 mL of 2.50 M HCl are added to 400.0 mL of 5.00 M HCl. volumes are additive, the final concentration is?

Question

a) 3.65 M
b) 3.83 M
c) 4.17 M
d) 4.33 M
e) 4.50 M

Answer 1

(350*2.5)+(400*5)/(350+400)=3.83M

Answer 2

We use:

C1V1 + C2V2 = C3V3
(2.5 M)(350 mL) + (5.0 M)(400 mL) = C3 (350 + 400 mL)

We solve for C3:

C3=3.83 M

So, the answer is option b)

That's It!

Good Luck!