Use the given conditions to write an equation for the line in slope-intercept form.?

Question

Passing through (2,2) and perpendicular to the line whose equation is y=1/8x +3

Answer 1

perpindicular means the slope is the negative reciprical. the slope of the perpindicular line is 1/8 so the slope of your line will be -8. it passes through 2,2 so:
y=-8x+b
2=-8*2+x
2=-16+b=18

y=-8x+18

Answer 2

The slope-intercept form is y = mx + b where m is the slope and b is the interception with y.

As it must be perpendicular to y = (1/8)x + 3 we have m = -8 (the inverse and symmetric of 1/8)

The equation is now y = -8x + b

As it must pass through (2,2) we have 2 = -8.2 + b and b =18

Finally y = -8x + 18

Answer 3

as line is perpendicular therefore
ax+by+c=0
then line perpendicular to it becomes
bx-ay+c'=0

now applying the given concept we get
1/8x-y+3=0
-x-1/8y+c'=0
we know that it passes through (2,2)
then
-2-1/8*2+c'=0
c'=9/8
therefore equation is
x+1/8y-9/8=0
8x+y-9=0 (ans)

Answer 4

y = 8x -14