A truck travelin at a stoplight. when th elight turns green, it accelerates at 2.0m/2 squared. at the same?

Question

instant, a car passes the truck goin 14m/s where and whn does the truck catch up witht the car
from the time the light turns green in seconds
from the location at which the vehicles start

Answer 1

I suppose you mean a=2m/s^2

you need the formula for constant acceleration for the truck
st=1/2*a*t^2 ; a=acc in m/s^2, t=time in sec

and you need the formula for constant velocity for the car
sc=v*t ; v=velocity in m/s

in both case s is the distance has to be the same for both vehicles

so we have
st=sc <=>
v*t=½*a*t^2<=> 0=½*a*t^2-v*t=
t(½*at-v)=> t=0 or ½*at-v=0 =>
t=2*v/a)=2*14/2=14s
==================
ofcause the vehicles are at the same point to t=0

so we use t=14s and put in to sc=v*t=>
sc=14*14=196m
============

Answer 2

Assume you mean 2 meters/second squared. 2.0m/2 squared doesn't make sense.

Assume the truck is stopped at the light, which is not what the question says.

Assume acceleration is constant, which is not like any truck I know.

Then, the answer is found through simple derivatives.