Redox and Non-Redox Reactions?

Question

For each of the following reactions, answer:
True or False? -- "This is an oxidation-reduction (redox) reaction."

3KCN(aq) + 2KMnO4(aq) + H2O(l) 3KCNO(aq) + 2MnO2(s) + 2KOH(aq)

4Br2(aq) + H2S2O3(aq) + 5H2O(l) 8HBr(aq) + 2H2SO4(aq)

Hg2Cl2(s) + 5HNO3(aq) 2Hg(NO3)2(aq) + HNO2(aq) + 2HCl(aq) + H2O(l)

6KCN(aq) + FeCl3(aq) K3Fe(CN)6(aq) + 3KCl(aq)

3Cl2(aq) + 6NaOH(aq) NaClO 3(aq) + 5NaCl(aq) + 3H2O(l)

10HNO3(aq) + 4Zn(s) 4Zn(NO3)2(aq) + NH4NO3(aq) + 3H2O(l)

Na2SO3(aq) + H2SO4(aq) Na2SO4(aq) + SO2(g) + H2O(l)

2HNO3(aq) + CuO(s) Cu(NO3)2(aq) + H2O(l)

Answer 1

For each of the following reactions, answer:
True or False? -- "This is an oxidation-reduction (redox) reaction."

3KCN(aq) + 2KMnO4(aq) + H2O(l) 3KCNO(aq) + 2MnO2(s) + 2KOH(aq)
True: Mn goes from +6 in KMnO4 to +4 in Mn02. N goes from -3 in KCN to +1 in KCNO.

4Br2(aq) + H2S2O3(aq) + 5H2O(l) 8HBr(aq) + 2H2SO4(aq)
True: Br goes from neutral in Br2 to -1 in HBr. S goes from +4 in H2S2O3 to +6 in H2SO4.

Hg2Cl2(s) + 5HNO3(aq) 2Hg(NO3)2(aq) + HNO2(aq) + 2HCl(aq) + H2O(l)
True: Hg goes from +1 in Hg2Cl2 to +2 in Hg(NO3)2. N goes from +5 in HNO3 to +3 in HNO2.

6KCN(aq) + FeCl3(aq) K3Fe(CN)6(aq) + 3KCl(aq)
False. Fe stays at +3 in FeCL3 and +3 in K3Fe(CN)6. CN stays at -1 in KCN and K3Fe(CN)6.

3Cl2(aq) + 6NaOH(aq) NaClO 3(aq) + 5NaCl(aq) + 3H2O(l)
True: Cl goes from nuetral in Cl2 to -1 in NaCl. Cl goes from nuetral in Cl2 to +1 in NaClO.

10HNO3(aq) + 4Zn(s) 4Zn(NO3)2(aq) + NH4NO3(aq) + 3H2O(l)
True: Zn goes from nuetral in Zn to +2 in Zn(NO3)2. N goes from +5 in HNO3 to -3 in NH4NO3 (on the NH4 side).

Na2SO3(aq) + H2SO4(aq) Na2SO4(aq) + SO2(g) + H2O(l)
False S stays at +4 in Na2SO3 and SO2. S stays at +6 in H2SO4 and Na2SO4. THIS ONE IS TRICKY!
The reaction is the Na and H2 swap from sulfate to sulfite, and then the H2SO3 splits into H2O(l) and SO2(g). The S maintains the same charge throughout--don't be confused by the multiple forms of S (sulfate and sulfite).

2HNO3(aq) + CuO(s) Cu(NO3)2(aq) + H2O(l)
False Cu stays at +2 in CuO and Cu(NO3)2, and N stays at +5 in HNO3 and Cu(NO3)2.

Answer 2

to be sure that a redox reaction to ensue, 2 components could substitute electrons and show diverse oxidation numbers A. basically finding at it I see that no component replaced oxidation selection so it quite is truly not a redox reaction NON REDOX B. here I see that Li is going from a Li+a million to a Li 0 jointly as Na is going from an Na 0 to an Na+a million. Electrons are exchanged. it quite is a redox reaction REDOX

Answer 3

Redox Reaction.- There is always a change in oxidation number of elements that take part of reaction.

So,
1, 2, 3, 5, 6, 7 are REDOX that is because:

1: Mn(7+) ----> Mn(4+)
2: Br2(0) -----> Br(-1)
3: N(5+) ------> N(3+)
4: No change in oxidation number - NO Redox
5: Cl2(0) ------> Cl(5+), Cl(1-)
6: Zn(0) ------> Zn(2+)
7:S(5+) ------>S(4+)
8:No change in Oxidation number - NO Redox

Answer 4

1, 2, 3, 5, 7, 8 are redox (I think)