An electron that is expelled from the back of a T.V is traveling at about 3.4000m/s horizontally toward the front of T.V screen which is on average 0.45m away. How far does the electron drop before hitting the pixels on the T.V to cause a fluorescence of the pixel on the front( a color TV)
2006-10-09 07:44:52 · 3 answers · asked by water yu 3 in Science & Mathematics ➔ Physics
time it takes to reach screen = .45/ 3.4 = .1323 seconds.
Yt = y0 + vt - 1/2g t ^2
y0 = 0 , v = 0
falls = 0.0857 meters
2006-10-09 07:55:09 · answer #1 · answered by leikevy 5 · 0⤊ 0⤋
This can be solved using simple kinematics. Think of the problem the same way you would as if you threw a ball at the same velocity as the electron's initial velocity and how far the ball would fall vertically before hitting something 0.45m away.
2006-10-09 14:50:32 · answer #2 · answered by ohmneo 3 · 0⤊ 0⤋
0.45 m / 3.4 m/s = 0.13 s
x(t) = 0.5 * a * t * t + v0 * t + x0
a = -9.8 m/s/s, v0 =0, x0 = 0
x(0.13s) = 0.086 m
2006-10-09 14:56:14 · answer #3 · answered by feanor 7 · 0⤊ 0⤋