You multiply the brackets out and then add (or subtract) the like terms
So if you expand it out first - the first bracket will give you
6a - 3b + 12 c
and then you add the contents of the second bracket
You should wind up with a big long row of a's b's and c's which you can add or subtract from each other to get your answer
2006-10-09 06:05:19
·
answer #1
·
answered by Orinoco 7
·
0⤊
0⤋
a^2+ 2b = 6 ------------(a million) b^2+ 4c = – 7 -----------(2) c^2+ 6a = –13 --------- (3) alongside with 3 equations: a^2 + b^2 + c^2 + 6a + 2b + 4c = –14 or a^2 + b^2 + c^2 + 6a + 2b + 4c + 14 = 0 you should set up the words to variety desirable sq. (a^2 + 6a + 9) + (b^2 + 2b + a million) + (c^2 + 4c + 4) = 0 (a + 3)^2 + (b + a million)^2 + (c + 2)^2 = 0 equating each and every and each bracket to 0 (a + 3)^2 = 0 (b + a million)^2 = 0 & (c + 2)^2 = 0 subsequently a = – 3, b = –a million & c = – 2 putting the values of a, b, & c interior the a^2+b^2+c^2 a^2 + b^2 + c^2 = (– 3)^2 + (–a million)^2 + (–2)^2 = 9 + a million + 4 = 14
2016-11-27 02:49:01
·
answer #2
·
answered by mehboob 3
·
0⤊
0⤋
Just take it step-by-step:
3(2a - b + 4c) + 2(a - 2b + c)
Distribute the 3 and the 2:
6a - 3b + 12c + 2a - 4b + 2c
Combine like terms:
6a - 3b + 12c + 2a - 4b + 2c
6a + 2a - 3b - 4b + 12c + 2c
8a - 7b +14c
Good luck in your classes.
2006-10-09 06:12:20
·
answer #3
·
answered by Mitch 7
·
0⤊
0⤋
3(2a - b + 4c) +2(a - 2b +c)
= 6a - 3b + 12c + 2a - 4b + 2c
= 8a - 7b + 14c
Hope it helps!!!
Boffdude xxx
(*^_^*)
2006-10-09 06:16:39
·
answer #4
·
answered by Boffdude 2
·
0⤊
0⤋
multiply out each of the brackets - 6a-3b+12c+2a-4b+2c then do the sum - 8a-7b+14c
2006-10-09 06:19:55
·
answer #5
·
answered by Danielle A 1
·
0⤊
0⤋
6a-3b+12c+2a-4b+2c=
8a-7b+14c
2006-10-10 01:11:22
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
Adding to Vals answer (above)
8a -7(b+2c)
2006-10-09 06:12:01
·
answer #7
·
answered by Trevor h 6
·
1⤊
0⤋
you need to multiply out:
8a-7b+14c
get a tutor since you aren't very good at maths
or this ste can help you with your maths:
http://www.bbc.co.uk/schools/ks3bitesize/maths/
2006-10-09 07:22:37
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋
=6a-3b+12c+2a-4b+2c
=8a-7b+14c
2006-10-09 06:58:06
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋
6a-3b+12c+2a-4b+2c
Ans: 8a-7b+14c
2006-10-11 12:22:28
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋