2abc^-3/-3a^-2b^2c^-1
2006-10-09 05:29:02 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i meen how do u write it without negative exponants?
2006-10-09 05:29:55 · update #1
-2a^3/3bc^2
2006-10-09 05:32:09 · answer #1 · answered by bequalming 5 · 0⤊ 0⤋
A negative exponent in the numerator can always be replaced by a positive exponent in the denominator, and vice versa. So you need to swap the locations of c^-3, a^-2, and c^-1. That will give you 2aba^2c/-3b^2c^3. When you simplify that, you get -2a^3bc/3b^2c^3. Then you subtract exponents in the numerator from those in the denominator to get -2a^3/3bc^2.
2006-10-09 12:33:29 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
Use a^x / a^y = a^(x-y) to get:
(-2/3)a^(1-(-2))b^(1-2)c^(-3-(-1)) =
(-2/3)a^3 b^(-1) c^(-2)
2006-10-09 12:30:38 · answer #3 · answered by James L 5 · 0⤊ 0⤋