2006-10-09 05:05:37 · 22 answers · asked by jammerjaws 1 in Science & Mathematics ➔ Mathematics
5 ways.
If he can choose 2 chickens to eat at a time, then he only has 5 choices.
Or maybe 1 way. Because each time he eats a chicken / chickens, it's only 1 way / style.
.
2006-10-09 05:15:43 · answer #1 · answered by Spica 4 · 0⤊ 1⤋
45 ways. he can first choose 1 chicken out of 10, so there are 10 ways; he can then choose the second chicken from the remaining 9, for 9 additional second choices for each of the first choice. So there are 90 choices. But choosing chicken A first and chicken B second is the same as choosing B first and A second. So half of the 90 choices are duplicative. Hence 45 choices.
2006-10-09 12:08:51 · answer #2 · answered by WoodyBretton 3 · 0⤊ 0⤋
you would see how many ways you could combine chicken A with all the others then B and so fourth so you would be adding
9, 8, 7, 6, 5, 4, 3, 2, 1 and that gives you a total of 45 ways
btw
wolves can eat chickens because they aren't sentient and don't know any better.
people shouldn't
I've been vegetarian for 3 years.
It's not that hard..
2006-10-09 12:10:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The number of ways to choose k objects from a set of n is given by the binomial coefficient
C(n,k) = n! / [k!(n-k)!]
In this case, n=10 and k=2, so you have
C(n,2) = 10! / [2!8!] = 8!*9*10 / [2*8!] = 9*10/2 = 45
so there are 45 ways.
2006-10-09 12:10:04 · answer #4 · answered by James L 5 · 0⤊ 0⤋
10-8=2
2006-10-09 12:07:58 · answer #5 · answered by Chaparrita !!!!!! 2 · 0⤊ 1⤋
that is your home work my little friend!!!!
the 1st with the rest= 9
the 2nd with the rest=8 (because the 2nd with the 1st was already)
the 3rd with the rest=7 (because 1-3 and 1-2 were already)
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the 9 with the rest=1 (all were there ecept 9-10)
the 10 with the rest = 0 becasue we have that ones already there
the answer 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45
2006-10-09 12:17:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
10 * 9 = 90 ways of eating chicken
2006-10-09 12:07:10 · answer #7 · answered by DanE 7 · 0⤊ 0⤋
i believe it's 10+9+8+7+6+5+4+3+2+1. (or 10!) if you go down the line of chickens and pair each one with each other chicken but with no repeats. i think this equals 55, if i added right. i could be completely wrong. it's been years since i've taken a math class.
2006-10-09 12:16:28 · answer #8 · answered by practicalwizard 6 · 0⤊ 1⤋
15
2006-10-09 12:07:57 · answer #9 · answered by Anonymous · 0⤊ 1⤋
About 90 or so, depending on how many leave while he is it eating the first.
10 choices for the first chicken, 9 for the second, product equals 90
2006-10-09 12:08:30 · answer #10 · answered by piercesk1 4 · 0⤊ 0⤋