2006-10-09 03:58:53 · 11 answers · asked by Aqsaqqal D 1 in Science & Mathematics ➔ Mathematics
Guys, some of you get confused, and write about 9^81... NO :)
9^9 = 387420489... SO! The REAL QUESTION IS,
is (9^9)^9, or 387420489 ^ 9 LARGER/SMALLER than
9(9^9), or 9 ^ 387420489???
2006-10-09 04:10:50 · update #1
Guys, some of you get confused, and write about 9^81... NO :)
9^9 = 387420489... SO! The REAL QUESTION IS,
is (9^9)^9, or 387420489 ^ 9 LARGER/SMALLER than
9(9^9), or 9 ^ 387420489???
To ones that say identical, NOT RIGHT...
3^(3^3) = 3^27 = 7625597484987
BUT!
27^3 = 19683.......
2006-10-09 04:25:48 · update #2
9^(9^9) >> (9^9)^9
Because the power of 9^9 in the exponant is much larger than having 9^9 in the base.
For example:
3^(3^3) = 3^27 = 7.6x10^12
(3^3)^3 = 27^3 = 19683
For any positive number greater than 2 the larger exponant will be larger.
2006-10-09 04:35:25 · answer #1 · answered by Mariko 4 · 2⤊ 1⤋
"9^(9^9)"
9^(387420489)
=OVERFLOW
"(9^9)^9"
(387420489)^9
=1.966270505*10^77
So apparently "9^(9^9)" is larger since the other number appeared on my calculator, while "9^(9^9) didnt.
Sorry that I couldn't give you exact numbers for the first problem though.
2006-10-09 04:10:13 · answer #2 · answered by ViCKi!™|` 5 · 0⤊ 0⤋
the former is going to be MUCH larger
it's pretty easy to understand intuitively: with 9^(9^9) you're using a huge exponent of 9^9. And if you've looked a bit at exponential functions, pretty quickly and barring special cases, it is the exponent that matters. In the second case you've got a modest number, 387'420'489, taken to just the 9th power.
2006-10-09 04:16:45 · answer #3 · answered by AntoineBachmann 5 · 0⤊ 0⤋
9^(9^9) = 9^387420489 --> LARGER
(9^9)^9 = 9^81
2006-10-09 04:04:05 · answer #4 · answered by Uncle Rodri 1 · 1⤊ 2⤋
9^(9^9)
2006-10-09 04:00:48 · answer #5 · answered by schvan 2 · 1⤊ 1⤋
9^(9^9) is much greater than (9^9)^9.
(9^9)^9 = 9^(9*9) = 9^81, which is much less than 9^(9^9).
2006-10-09 04:07:03 · answer #6 · answered by David Y 5 · 1⤊ 2⤋
9^(9^9)=9^9^9=9^81
(9^9)^9=9^9^9=9^81
they are equal.
2006-10-09 04:11:17 · answer #7 · answered by Anonymous · 0⤊ 3⤋
they are the same...... that is a known rule.....brackests does not afeect here.
for example:
2^(2^2)=2^4=16
(2^2)^2=4^2=16 aslo
OK.........
2006-10-09 04:12:17 · answer #8 · answered by mozakkera 2 · 0⤊ 3⤋
Absolutely identical...
Simplify and solve...
2006-10-09 04:19:49 · answer #9 · answered by harsh 1 · 0⤊ 2⤋
mozakkera is correct. They are the same.
2006-10-09 04:18:38 · answer #10 · answered by galford_sg 2 · 0⤊ 2⤋