Math Problem!!?

Question

Prove that 4=3 and state the wrong statement :D!!

Answer 1

Proof:
Suppose:
a + b = c

This can also be written as:

4a - 3a + 4b - 3b = 4c - 3c

After reorganising:

4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:

4 * (a+b-c) = 3 * (a+b-c)
4 * (a+b-c)/a+b-c) = 3 * (a+b-c)/(a+b-c)
Remove the same term left and right:

4 = 3

The first one is also correct but he doesnt give the wrong statement!! the wrong statement is 4 * (a+b-c)/a+b-c) = 3 * (a+b-c)/(a+b-c) because a + b = c transpose a+ b - c = 0 you cant divide by zero that's why this is a math weakness h3h3h3!!! because you have true statements but you cant have the true answers!!

^^!!

Answer 2

This "proof" came up a couple of days ago.

Assume x+y=a.

Then (4-3)x + (4-3)y = (4-3)a.

Rearrange:

4x + 4y - 4a = 3x + 3y - 3a.

Factor:

4(x+y-a) = 3(x+y-a)

Now, divide through by x+y-a, and you get:

4=3

Answer 3

there is no such proof.
and whatever statements pointing into that conclusion of course
must have an error.

Answer 4

Since when did they start putting letters in sums!!!!!!