the water 4 feet from the base of the wall How far did Jenny Jump jump altogether?
2006-10-09 02:24:13 · 3 answers · asked by osurules 1 in Science & Mathematics ➔ Mathematics
5 feet.
The problem is a very poorly thought out word problem considering there are other factors that do influence the outcome of a jump.
So it becomes Pythagorean Theorm, as the jump is on a triangle and we only have two sides of the triangle.
a² + b² = c²
3² + 4² = c²
9 + 16 = 25
The Square Root of 25 is 5.
So five feet.
2006-10-09 02:38:28 · answer #1 · answered by Ryan 4 · 0⤊ 0⤋
If you draw a picture of what's going on, you have a right triangle, with the hypotenuse being Jenny's path into the water, one vertical leg that's 3 ft high, and one horizontal leg that's 4 ft long.
By the Pythagorean theorem, the distance she jumped, d, satisfies
d^2 = 3^2 + 4^2
so
d^2 = 9 + 16 = 25
meaning she traveled 5 feet.
2006-10-09 02:32:06 · answer #2 · answered by James L 5 · 0⤊ 0⤋
hmmm you need some more details here. it will depend on the angle jumped at, and what do you mean 4 feet from the base of the wall?
2006-10-09 02:28:20 · answer #3 · answered by tsunamijon 4 · 0⤊ 0⤋