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5 answers

Except the one that isn't here.

But any x > 2 will work ☺


Doug

2006-10-08 18:55:21 · answer #1 · answered by doug_donaghue 7 · 0 0

2x + 3 > 7
minus both parts by 3, we have:
2x > 4
divide both parts by 2, we have:
x >2

so, x is on the interval of 2 to infinity, except 2.

2006-10-08 19:36:01 · answer #2 · answered by visal m 1 · 0 0

2x + 3 > 7
2x > 4
x >2

So, any number less than or equal to 2 would not be a solution to this question.

2006-10-08 20:37:24 · answer #3 · answered by Math teacher 2 · 0 0

X less than or equal to 2

2006-10-08 18:57:45 · answer #4 · answered by iamantonio 2 · 0 0

One and two are not solutions.

2006-10-08 18:55:30 · answer #5 · answered by Anonymous · 0 0

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