hexagon
octogon
nonagon
decagon
2006-10-08 17:46:31 · 9 answers · asked by kneegr0w_j0hn 2 in Science & Mathematics ➔ Mathematics
nonagon
same conclusion via different route. If there are n diagonals drawn, that means (n+1) triangles are created. That in turns means there [(n+1) + 2] = (n+3) sides to the polygon.
So if n = 6, (n+3) = 9 and that is a nonagon.
2006-10-08 17:58:47 · answer #1 · answered by Anonymous · 2⤊ 0⤋
It's a nonagon . You can see this by drawing several polygons and drawing diagonals. If you do this you will notice that from any vertex of any regular polygon the are three vertexes you cannot draw a diagonal to --itself, and the two vertexes next to the one you are drawing from . If you can draw 6 diagonals, add three and the polygon is nine sided or a nonagon.
2006-10-09 01:14:14 · answer #2 · answered by True Blue 6 · 0⤊ 0⤋
A nonagon - 9 sided polygon.
In order for there to be 6 diagonals, there needs to be 6 points that are not already directly connected the the starting point. Plus there are the two points that are directly connected to the starting point, and the starting point itself for a grand total of 9 points, and hence 9 sides. The two directly connected points are part of the polygon and thus are not diagonals.
2006-10-09 00:50:46 · answer #3 · answered by mattbrunner82 2 · 1⤊ 0⤋
nonagon...
leaving the 2 adjacent points(cos lines with them forms sides of the polygon) we need six more points to draw diagonals.
now we have nine points altogether so its a nanogon
2006-10-09 00:56:44 · answer #4 · answered by just08in 2 · 0⤊ 0⤋
hexagon
2006-10-09 02:12:53 · answer #5 · answered by sameer 2 · 0⤊ 0⤋
hexagon
2006-10-09 01:05:44 · answer #6 · answered by dream f 1 · 0⤊ 0⤋
nonagon
2006-10-09 00:53:58 · answer #7 · answered by marinam 2 · 0⤊ 0⤋
decagon
2006-10-09 00:52:05 · answer #8 · answered by safrodin 3 · 0⤊ 0⤋
octogon
2006-10-09 00:49:49 · answer #9 · answered by Apoorva 3 · 0⤊ 0⤋