in a beams ultracentrifuge, the rotor is suspended magnetically in a vacuum. Since there is no mechanical connection to the rotor, the only friction is the air resistance due to the few air molecules in the vacuum. if the rotor is spining with an angular speed of 5.0^105 rad/s and the driving force is turned off, its spinning slows down at an angular rate of 0.40 rad/s2.
How long does the rotor spin before coming to rest?
During this time, through how many revolutions does the rotor spin?
Okay, I need some help with this problem, what are the formulas i would use to solve this?
2006-10-08 17:36:14 · 1 answers · asked by Trevor M 1 in Science & Mathematics ➔ Physics
If the initial angular speed is w0 rad/sec, and in slows down by r rad/sec each second, divide w0 by r to get the time it takes to stop ts. The average angular speed is w0/2 (starts at w0, ends at 0, and is linear in between) Each revolution takes 2π radians, so the total revolutions is (w0/2 * ts)/2π
2006-10-08 17:48:33 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋