Factor Completely. 3x(x-5y)-8(x-5y) please show me how to do this in detail?

Question

Factor Completely. 3x(x-5y)-8(x-5y) please show me how to do this in detail

Answer 1

easy

take(x-5y) common in both terms we get

(x-5y)(3x-8) using distributive law of multiplication

Answer 2

3x(x-5y) - 8(x-5y) (1)

I sometimes find it helpful to make the following change.
Subtracting 8 is the same as adding a negative 8. So, equation (1) can be rewritten as follows.

3x(x-5y) + (-8)(x-5y) (2)

See the difference? It'll be helpful in a moment.

Now, start with the first part and multiply 3x through the variables in the parentheses. Then, do the same to the second term, by multiplying the (-8) through the variables in the second set of parentheses.


3x(x-5y) + (-8)(x-5y) (2, from above)

= (3x^2 - 15xy) + (-8x + 40y)

You can drop the parentheses which I added for clarity now and simply write

=3x^2 - 15xy -8x + 40y


Hope this helps!

Answer 3

The way I see it, the only thing you can do now is make it
(3x-8)(x-5) because notice the first two terms (not numbers...terms) 3x and -8 (yes, it's negative) are both in one set of parentheses and x-5 is in another? Let's work backwards. The original problem was probably something like: Factory completely. 3x^2-15xy-8x+40y. (note: the "^2" means squared.) First, you separate them into two to get: 3x^2-15xy as one and 8x+40y as the other. Then, factor out 3x from 3x^2-15xy to get 3x(x-5y). After that, factor out a -8 from -8x+40y to get -8(x-5y). You have to factor out a -8 instead of an 8 because you need to have the x positive. Now that you have 3x(x-5y)-8(x-5y), you can factor it into (3x-8)(x-5y).

Answer 4

This situation is somewhat messy, in spite of if it is available. :) First, observe that each and every physique 3 words are divisible by using 5. meaning you are able to turn it into: 5(y^2 - 18y + 80 one) bypass away that 5 outdoors the parentheses on my own for now. The trend that something of the equation is in (a^2 - 2ab - b^2) tells us that the factored form of this situation is (a - b)^2. Assuming a is y, we can end that the selection that as quickly as doubled provides -18 and expanded provides 80 one is -9. So the factored trinomial is: (y - 9)(y - 9) be useful to function the 5 lower back in there on your very final answer, and set it equivalent to 0: 5(y - 9)(y - 9) = 0.

Answer 5

3x(x-5y)-8(x-5y)

The common factor is (x-5y).
So extracting that factor the answer is:
(x-5y) (3x -8)

Answer 6

3x(x-5y)-8(x-5y)

3x^2 - 15xy - 8x + 40y

x(3x-8) 5y(3x+8)

(x-5y)(3x+8)

Answer 7

(3x-8)(x-5y). To make this easier to see, let x-5y=a. 3xa-8a= (3x-8)a

Answer 8

(3x-8)(x-5Y)

Answer 9

3 x (squared) - 15xy-8x +40y

I think I could be wrong... u can't really do anything after this... but like I said it could be wrong wait till other people answer...compare... :)

Now that i think about it may be really wrong!!!