Solve. (x - 7)(x - 5)=0?

Question

Solve. (x - 7)(x - 5)=0
Show th eowrk so I can learn how to do this

Answer 1

0 times anything is zero so you have to get each quantity to be zero so:
(x - 7)=0 &
(x - 5)=0
or
x - 7=0 &
x - 5=0

from there you just solve for x which gives you:
x = 5 and x = 7



here is how you can check your answer:

for x = 5,
(x - 7)(x - 5)=0
(5 - 7)(5 - 5)=0
(-2)(0) = 0


for x = 7,
(x - 7)(x - 5)=0
(7 - 7)(7 - 5)=0
(0)(2) = 0

I hop it helped.
Email me at [e-mail] If you have anyother math questions.

Answer 2

The solution is not difficult, but first let's back up and start from the beginning.

Usually you will be given an equation to solve for x.
it might be x^2 -12x+35=0
One way to solve this equation is to factor it.
If you do so you get (x-7)(x-5)=0

Now that you have arrived at these factors, what next?
Well, since both factors multiplied together equal zero, then either x-7=0, or x-5=0
So x is 7 or 5.
That is your solution .
x=7,5

Answer 3

Maybe you should use a tiny bit of brain power. You have some, don't you? All the work is already done...
If you can't understand that the answers are 7 and 5, you are in trouble indeed.
There's nothing to "show": you just read the answer....
Let me put it very explicitly:
7-7=0 and 5-5=0.
Real hard I know! Real tough all that crazy math stuff!

Answer 4

Set each term equal to 0.
x-7=0
x-5=0

Then solve each one.
x-7+7=0+7
x=7

x-5+5=0+5
x=5

Answer 5

since the equation equals 0, one or both of the factors on the left must equal zero
thus, x-7=0 or x-5-0
so x=7 or x=5

Answer 6

Set each quantity to zero and solve for x.

x - 7 = 0

x = 7

Do the same for the other quantity.

x - 5 = 0

x = 5

Answers: {x = 5 and x = 7}

I hope this helps.
Guido

Answer 7

What do you mean by "solve"?
the roots are
x-7=0
x=7
&
x-5=0
x=5

if you want it multiplied use FOIL: 1st terms, x*x; outside terms, x*(-5); inside terms,
-7*x & last terms, -7*(-5)
(x - 7)(x - 5)=0
x^2-5x-7x+35=0
x^2-12x+35=0

Answer 8

(x - 7)(x - 5)=0
X^2-7X-5X+35=0
X^2-12X+35=0

The answer are
X=5,X=7

X^2-12X+35=0
(5)^2-12(5)+35=0
25-60+35=0
60-60=0 correct

X^2-12X+35=0
(7)^2-12(7)+35=0
49-84+35=0
84-84=0 correct

Answer 9

In general if (x-a) (x-b) (x-c) (x-d) ......=0then x= a: b:c;d..... therefore now since (x-7)(x-5)=0 x= 7;5.