can u solve this
2006-10-08 15:09:02 · 6 answers · asked by estela2829@sbcglobal.net 1 in Education & Reference ➔ Primary & Secondary Education
Sure
May:x-86=(115)-86
Sue:x=(115)
x+x-86=144
2x-86+86=144+86
2x=230
2x/2=230/2
x=115
back to the key to substitute x.
Sue has 115 Beads and May has 29 beads.
2006-10-08 15:24:47 · answer #1 · answered by sparkful 1 · 0⤊ 0⤋
Let's say May's beads = m
Then Sue's beads would be m + 86 because Sue would have 86 more than May.
m + m + 86 = 144
2m = 58
m = 29
Sue = 115
2006-10-08 22:13:32 · answer #2 · answered by PatsyBee 4 · 0⤊ 0⤋
Yes I can solve this.
Here it is:
May + 86 = Sue, right? Let's put it into better algebraic terms:
m + 86 = s
Sue + May = 144, right?
m + s = 144
Since we know that s=m+86, we can substitute that:
m + (m+86) = 144
2m + 86 = 144
subtract 86 from each side
2m = 58
divide each side by 2
m=29
May has 29 beads.
2006-10-08 22:10:38 · answer #3 · answered by glurpy 7 · 0⤊ 1⤋
May has 29 beads
2006-10-09 05:28:21 · answer #4 · answered by sweetangel 2 · 0⤊ 0⤋
may has 29
144 = m + s
s - 86 =m
144=s+m
144=s+ (s-86)
144 = 2s - 86
230 = 2s
s = 115
115-86=29
2006-10-08 22:16:01 · answer #5 · answered by JellyBeans17 3 · 0⤊ 0⤋
58 BEADS.
2006-10-08 22:25:17 · answer #6 · answered by HADITDUN 5 · 0⤊ 0⤋