2006-10-08 14:32:02 · 6 answers · asked by Lori 1 in Science & Mathematics ➔ Mathematics
why do you guys show him the answer? why not show your work and the steps so that he can learn how to do it?
2006-10-08 14:40:42 · answer #1 · answered by Kung Fu Badger 3 · 0⤊ 1⤋
12x^4y^3 + 16x^3y^3 - 20x^3y^4
= 4x^3y^3(3x + 4 - 5y)
2006-10-08 21:35:43 · answer #2 · answered by cmdr2006 2 · 0⤊ 0⤋
the common factor in the numerical digits is a 4
the common factor in the x variable is x^3
the common factor in the y variable is y^3
take out these factors and you're left with
(4x^3y^3)(3x + 4 - 5y)
now if you wanted to factor further, factor a 4xy out of the first set of parenthesis
(4xy)(x^2y^2)(3x + 4 - 5y)
you can go one more step, factor an xy out of the second set of parenthesis
(4xy)(xy)(xy)(3x + 4 - 5y)
final answer
2006-10-08 21:40:20 · answer #3 · answered by Mudmutt 2 · 0⤊ 0⤋
4x^3y^3(3x+4-5y)
2006-10-08 21:35:35 · answer #4 · answered by Amy C 2 · 0⤊ 0⤋
4x^3y^3(3x+4-5y)
2006-10-08 21:34:47 · answer #5 · answered by bluegasou 1 · 0⤊ 0⤋
doesnt make any sense
2006-10-08 21:34:47 · answer #6 · answered by dufus 2 · 0⤊ 1⤋