so i am tutoring my little brother on this and this is what i told him..
well i made him write out proportions...... a percent is always out of 100, and when a number is an "is" then it is on top and "of" is on the bottom........ so your proportion would look like this:
x% 17 >>>>is
--- = ------
100 68>>>>of
now you cross multiply
100 * 17 and then divide by 68 and you get x or the percent
hope i helped and didnt confuse you ;-)
2006-10-08 13:51:38
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answer #1
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answered by Jen 2
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17/68*100=25%
40% of x=2
40/100 x=2
4/10 x=2
2/5 x=2
x=2*5/2
x=5
2006-10-08 14:33:55
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answer #2
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answered by moosa 5
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The easiest way to solve is to remember that (is/of=%/100).
So...(17/68=x/100)
cross-mulitply...17*100=68x
divide 1700 by 68 and you get x=25...therefore, 17 is 25% of 68.
For the next problem...(2/x=40/100)
cross-multiply...2*100=40x
divide 200 by 40 and you get x=5...therefore, 2 is 40% of 5.
2006-10-08 13:26:57
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answer #3
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answered by princess 1
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whilst given an expression which comprise x^2-3x-4, it could purely be factored yet can't be solved (using fact there is not any equivalent sign). whilst given an equation which comprise x^2-3x-4=0, this is factored then solved. See under. For quadratic equations in this style of ax^2 + bx + c = 0, there are 3 strategies to unravel it: a million) resolve by making use of making use of the formulation x = (-b ± ?(b^2-4ac))/(2a). The determinant is det=(b^2-4ac). If det>0 then there are 2 diverse genuine roots. If det=0 then there are 2 equivalent genuine roots. If det<0 then there are 2 diverse imaginary roots. 2) resolve by making use of factoring. occasion: 2x^2 - 3x - 5 = 0. Factoring the left side into (2x - 5)(x + a million)=0 then (2x-5)=0 or (x+a million)=0 x=5/2 or x= -a million 3) resolve by making use of ending up the sq.. (seldom used) making use of the appropriate sq. formulation ax^2 ± 2abx + b^2 = (a ± b)^2. word the midsection term coefficient of 2ab. Ex: x^2 - 3x - 10 = 0 changing the midsection term coeffiecient 3 into 2(3/2), x^2 - 2(3/2)x - 10 = 0 x^2 - 2(3/2)x = 10 including (3/2)^2 to the two factors so as that the left side is to have a suitable sq. style, x^2 - 2(3/2)x + (3/2)^2 = 10 + (3/2)^2 x^2 - 2(3/2)x + (3/2)^2 = 40 9/4 The left side is now in this style of a prefect sq.. comparing with the appropriate sq. formulation above, we've a=a million and b=(3/2), (x - 3/2)^2 = ?(40 9/4) Taking sq. root from the two side, (x-3/2)=+7/2 or (x-3/2)=-7/2 x=5 or x = -2 ending up the sq. is often utilized in parabola to locate the axis of symmetry and the optimal/minimum fee. Ex: y = x^2 - 3x - 10 ending up the quare for the appropriate hand side, y = x^2 - 2(3/2)x - 10 including and subtracting (3/2)^2, y = x^2 - 2(3/2)x + (3/2)^2 - 10 - (3/2)^2 y = x^2 - 2(3/2)x + (3/2)^2 - 40 9/4 y = (x - 3/2)^2 - 40 9/4 The axis of symmetry is x=3/2. The minimum y fee is -40 9/4. desire this helps.
2016-10-19 01:19:39
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answer #4
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answered by ? 4
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Well, my children learned this last year. You have to learn how to read the word problems.
When it says X "is" Y of what number, the "is" means equals. "Of" usually means multiplication. Therefore:
2 = 40% x ???
Now change the percentage to a decimal fraction.
2 = 0.40 x ???
Now, solve for ??? by dividing.
2 / 0.40 = ???
5 = ???
The answer is 5.
For the first problem, you want to solve for "what". So write the equation:
??? x 68 = 17
Divide to solve for ???.
??? = 17 / 68
??? = 0.25
If you want it as a percentage multiply the answer by 100.
??? = 0.25 x 100
??? = 25%
The answer is 25%.
2006-10-08 13:27:31
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answer #5
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answered by chonudi 3
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question 1) 25 percent (17/68)
question 2) 5 (2/40 * 100) *= x (multiply)
there ya go!
2006-10-08 13:19:10
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answer #6
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answered by magendazzler 2
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2 is 40% of 5.
1=20%. 20x5=100%
1x5=5
duh. i'm not even in 8th grade.
68 over 100 x 17 over 100. cross cancel, reduce, turn into a whole #.
2006-10-08 13:19:22
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answer #7
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answered by ♥Rayyhol♥ 4
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to find the answer for the first one
divide 17 by 68
to find the answer for the second one
divide 2 by .4
2006-10-08 13:18:17
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answer #8
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answered by Sasha 3
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