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velocity and acceleration

2006-10-08 12:34:14 · 10 answers · asked by lgenes_esc5161 1 in Science & Mathematics Physics

10 answers

motion with constant velocity means that the item is moving at a constant (stays the same) speed and motion with constant acceleration means that the item's speed in continually increasing.

2006-10-08 12:41:09 · answer #1 · answered by fat_albert_999 5 · 0 0

Motion At Constant Acceleration

2016-10-31 00:29:48 · answer #2 · answered by ? 4 · 0 0

Acceleration is a change in velocity with respect to time.
An object experiencing an acceleration is constantly changing velocity...if that acceleration is constant then its velocity will change at a constant rate.

An object which has a constant velocity experiences no acceleration.

Constant acceleration does not rule out a constant speed (since speed is not the same thing as velocity).
An object experiencing uniform circular motion experiences a constant [centripetal] acceleration, and because of this its velocity is continuously change; however, the object's speed is constant.

2006-10-08 12:51:19 · answer #3 · answered by mrjeffy321 7 · 0 0

Generally speaking... motion with constant velocity is a completely relative term where as motion with constant acceleration is absolute. There is no experiment to prove that you are in motion (and not everyone else) but you can prove that you are accelerating quite easily.

Mathematically speaking, the derivative of the formula of a the distant traveled for an object in constant velocity is a straight line. For the constant acceleration, it is the derivative of the derivative that is a straight line.

2006-10-08 12:40:42 · answer #4 · answered by John H 3 · 0 0

Motion with constant velocity means the speed is constant, it is not changing, it is a steady speed.

Motion with constant acceleration means the speed is not constant, rather it is increasing at a steady rate.

Ciao.

2006-10-08 12:41:31 · answer #5 · answered by jujubees 2 · 0 0

First component of your answer is fantastic this is while velocity is persevering with acceleration is 0. yet 2d section isn't ok. while physique is in sped up action its velocity isn't consistent whether it adjustments with time. The observe acceleration means that there is a metamorphosis in velocity. In an hassle-free occasion if a automobile is shifting with a persevering with velocity of 80km/s then v=80 km/s and a = 0. If its velocity adjustments say 80, 80 5, ninety, ninety 5, a hundred km/s at each succeeding 2d then velocity isn't consistent yet adjustments and a = 5km/s2

2016-10-02 02:28:29 · answer #6 · answered by lyon 4 · 0 0

No big words :
You leave from Los Angele's to San Diego at the speed of 55mph. with out going any faster or slowing down - that is motion(moving) at constant ( always the same either always going at the same speed or always going faster and faster) velocity (speed).

Then you come back from San Diego to Los Angeles going on to the free way at the speed of 55mph then going faster every time 55 then 65 then 75 and so and so on (constant acceleration= the rate at which something INCREASES in VELOCITY ) increase in speed......speed = velocity

2006-10-08 13:24:23 · answer #7 · answered by slickrickdesigns 3 · 0 0

To keep the velocity of your car going you need to continually have to feed it gas.Constant acceleration theoretically does not exist.Acceleration take two form ;one one moving against the field and the other with the field the field. In order to increase speed or accelerationyou need to add power.Acceleration is Really an hyperbolic function. Its never constant.

2006-10-08 13:00:00 · answer #8 · answered by goring 6 · 0 1

BIG DIFFERENCE...

a constant acceleration means an ever-increasing velocity, which means a constantly increasing kinetic energy and momentum

2006-10-08 12:39:38 · answer #9 · answered by arbiter007 6 · 0 0

One follows general relativity's equation, and one follows specific relativity's equation.

ie, in the first you cannot tell that you are moving, in the second, you can.

2006-10-08 12:40:11 · answer #10 · answered by iandanielx 3 · 0 0

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