For the experiment of drawing 2 marbles without replacement from a jar containing two red marbles, 3 blue marbles, 4 green marbles and 1 mauve marble.. find each of the following probabilities?..... I know that you do the probability of 1 - none for atleast problems, but I can't seem to figure this one out.
2006-10-08 12:32:30 · 5 answers · asked by wallabie22 1 in Science & Mathematics ➔ Mathematics
What is the probability that you will draw at least one green marble?
For the experiment of drawing 2 marbles without replacement from a jar containing two red marbles, 3 blue marbles, 4 green marbles and 1 mauve marble.. find each of the following probabilities?..... I know that you do the probability of 1 - none for atleast problems, but I can't seem to figure this one out.
2006-10-08 12:34:04 · answer #1 · answered by god knows and sees else Yahoo 6 · 0⤊ 0⤋
The probability of the first marble not being green is 6/10, since there are 4 green marbles.
The probability of not drawing a green marble the second time is 5/9.
The probability of both events occurring is (6/10)(5/9) = 1/3, so the chances of picking at least one green is 1-1/3 = 2/3.
2006-10-08 19:39:04 · answer #2 · answered by James L 5 · 0⤊ 0⤋
two red marbles, 3 blue marbles, 4 green marbles and 1 mauve marble=10 marbles
1st draw odds of a green marble are 4/10
2nd draw (remaining 6/10 odds)=4/9 so odds of drawinf at least 1 green marble are
P=4/10+(4/9)(6/10)=4/10+24/90=4/10+4/15=12/30+8/30=20/30=2/3
P=2/3
2006-10-11 19:48:05 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
1 - probability of no green marbles
1-(6/10*5/9) = 1 - 30/90 = 2/3
2006-10-08 19:48:20 · answer #4 · answered by bob h 3 · 0⤊ 0⤋
i really suck at math! i did this last year in grade 7 but never really got it. i could probably figure this out but im SO LAZY! and no school tomorrow for me cuz of thanksgiving so BOOYAH
i knwo im wasting your time here, sorry, but dont you think you should do your homework instead of us doing it for you?
2006-10-08 19:36:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋