Is it possible to factorise the equation:
x^(3/2) + a^(3/2)
(i.e. x to-the-power 3-over-2) If so, could someone provide a general method so that I can attempt this problem?
2006-10-08 12:15:52 · 3 answers · asked by Paul J C G 2 in Science & Mathematics ➔ Mathematics
KEiKo: The verb "factorise" is correct in the UK, which is where I am from.
2006-10-08 12:29:09 · update #1
Let z=x^(1/2), b=a^(1/2).
Then the equation becomes z^3 + b^3, which factors into
(z+b)(z^2 - bz + b^2)
so you have (x^(1/2) + a^(1/2))(x - a^(1/2)x^(1/2) + a).
2006-10-08 12:22:19 · answer #1 · answered by James L 5 · 0⤊ 0⤋
never mind, dude above answered it
Something to note: You cannot factor"ise" an equation. You can factor an equation. Learn how to modify your verbs correctly, or you will sound like an idiot.
2006-10-08 19:22:38 · answer #2 · answered by KEiKo 3 · 0⤊ 1⤋
ummm..
just like a^2 + b^2, even though they have the same exponent, still they can't be factored..
same thing with your problem, i guess we can't factor it out..
so it will stay the same..
2006-10-08 19:19:40 · answer #3 · answered by mermaid.marie 4 · 0⤊ 0⤋