the circle is this x^2+y^2=4, z=3
2006-10-08 12:15:50 · 4 answers · asked by Gum Yu Lo 1 in Science & Mathematics ➔ Mathematics
I gave you the correct answer to this question once before!!
Didn't you read it?!!
r = √(x^2+y^2) = √4 = 2
φ = φ; 0 ≤ φ ≤ 2π
z = 3
SEE:
http://answers.yahoo.com/question/index;_ylt=Ahm3cnGinQTtbs3sSjmZp6bsy6IX?qid=20061007222116AAi0jYo
.
2006-10-08 12:59:06 · answer #1 · answered by Scott R 6 · 0⤊ 0⤋
It is z=3 and r=2
2006-10-08 12:25:28 · answer #2 · answered by wild_turkey_willie 5 · 0⤊ 0⤋
Cylindrical coordinates are (r,theta,z), where r^2 = x^2 + y^2 and tan(theta) = y/x.
So, in cylindrical coordinates, x^2+y^2=4 becomes r^2=4, or r=2. The z=3 equation remains the same.
2006-10-08 12:24:17 · answer #3 · answered by James L 5 · 0⤊ 0⤋
a 3 dimensional circle ... hmmm
dont care for that discription ... you really just have a slice of a cylinder (at z=3)
convert the rectangular coordinates (x and y) to polar coordinates
2006-10-08 12:27:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋