I saw advertisements for the fourth one, and I'm just trying to figure out if it's the same girl playing Marney as it was in the first three. She still has that dimple in her chin, but it seems like she really thinned out. She doesn't have that baby face anymore. Is it the same girl?
2006-10-08 12:15:49 · 9 answers · asked by Anonymous in Entertainment & Music ➔ Television
I was wondering that too, bu I found out that they were diffrent people. The one in the last 3 movies was Kimberly J. Brown. And the one this year is Sarah Paxton. They do look the same, but they are diffrent people
2006-10-08 12:29:53 · answer #1 · answered by Amber R 2 · 0⤊ 0⤋
No because i don't think Sarah Paxton played the parts in the other ones... their was another movie where the main girl from 1-3 played the main charcter... it had something to do with 7 or 8 babies...
2006-10-08 19:26:40 · answer #2 · answered by Pie iz GOOD!!! 2 · 0⤊ 0⤋
I LOVE ALL OF THEM Holloweentown, Holloweentown 2 Kalabars revenge, Holloweentown High and Return to Holloweentown. I think she is the same girl and she does look different. She reminds me of Hiliary Duff She leaves television for some years and now she looks like she is on crack.
2006-10-08 19:19:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
no its a different girl. her name is sara paxton. she was in the movies "aquamarine" & "sleepover". she had blonde hair in them and she dyed in brown to look like marney.
2006-10-08 19:58:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I think its a new girl her name is Sara Paxton. I watch them there good movies.
2006-10-08 23:50:22 · answer #5 · answered by mth16us 4 · 0⤊ 0⤋
Her name is Sarah Preston I don't know if it is the same girl.
2006-10-08 19:25:51 · answer #6 · answered by Pantherempress 7 · 0⤊ 0⤋
no it isnt the same girl, they just got a girl who looks like her.
2006-10-08 19:17:17 · answer #7 · answered by Anonymous · 0⤊ 0⤋
no its not the same girl
2006-10-08 19:46:24 · answer #8 · answered by deed792 3 · 0⤊ 0⤋
no way
2006-10-08 19:16:59 · answer #9 · answered by Anonymous · 0⤊ 0⤋