If you have a graph of LN concentration on the Y axis and Time on the X axis, graphing the data gives you a Y=Mx+B, how would you use this to find the rate constant.
2006-10-08 12:02:19 · 5 answers · asked by cassandracorrao 3 in Science & Mathematics ➔ Chemistry
If this is a 1st order reaction (& if ln C vs t is a st line it is), the equation forconcentration as a fn of time is:
C(t)=C0*e^(-rt) or
ln (C(t))=ln(C0)-rt
the slope of the st line is the negative of rate constant: m=-r
2006-10-12 09:30:12 · answer #1 · answered by yupchagee 7 · 15⤊ 0⤋
Rate Constant From Graph
2016-11-04 21:08:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A zero order rate constant is a zero order rate constant. You can't fit it into a first order equation because the reaction proceeds differently with time, and moreover, the UNITS of the constants are not the same. If the reaction is truly zero order, the rate constant will be the slope of the line, and be in terms of moles reacted per unit time. Thus, you can determine the time frame of the reaction if you want to carry it out to be compatible with your timing equipment.
2016-03-17 04:19:37 · answer #3 · answered by Gregory 4 · 0⤊ 0⤋
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For a 0 order rxn M = kt dM/dt = k hence the slope of the graph will give u k i.e find out M2 - M1/ t2 -t1
2016-04-05 22:13:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋
M (the slope) is your rate constant.
2006-10-08 12:13:22 · answer #5 · answered by VTNomad 4 · 0⤊ 0⤋