Find an isosceles triangle that has the same area as its perimeter.?

Question

Please help me figure this problem out...

Answer 1

say sides = x each

perimeter = 3x

area = x^2 sqrt(3) / 4

set 3x = x^2 sqrt(3) / 4 ... divide both sides by "x"

3 = x * sqrt(3) / 4

x = 3 / (sqrt(3) / 4) = 4 * 3 /sqrt(3) = 4*sqrt(3)

so ........

if each side is 4 * sqrt(3), the perimeter and the area are
numberically the same .... (altho "units" of area are diferent from "units" of perimeter [length^2 vs length]

A = P = 12 * sqrt (3)

Answer 2

Unfortunately, this cannot be answered.

Area isn't the same as perimeter.

Perimeter would be a measure of length, i.e. ft, and area would be ft^2.

Regards,

Mysstere