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what is the force that the boulder has when it hits the ground? and what formula is used?

2006-10-08 11:29:07 · 6 answers · asked by Anonymous in Science & Mathematics Physics

no additional information is given. I understand that f=mass X acceleration. The only info on acceleration is: A=G
9.8m/SEC sq

2006-10-08 11:40:58 · update #1

6 answers

The question does not have sufficient information for you to solve for the actual force, since it doesn't even tell you how far the boulder falls to allow you to calculate the potential energy.

So, the problem is asking you to figure out what information you WOULD need to do the problem:

height to get the potential energy
stopping distance to dissipate the potential energy

force = work*distance

2006-10-08 12:38:11 · answer #1 · answered by arbiter007 6 · 0 0

does it bounce first? does it roll? how steep is the slope? is the boulder granite, sandstone, or shale? how heavily jointed or fractured is it - how many pieces is it going to break into when it hits the ground?

A 30 tonne boulder is likely going to vaporize and turn into dust upon impact, and probably won;t reach the bottom of the canyon in large peices. is that taken into account?

2006-10-08 11:34:39 · answer #2 · answered by dave_co_78 2 · 0 0

I'll do your home this one time. momentum = mass X velocity where velocity is the force of gravity in kilometers/sec/sec (I can recall it in English measure only 32 ft./sec/sec)

2006-10-08 11:41:38 · answer #3 · answered by Sophist 7 · 0 0

i dont know the answer but mass X acceleration =force

2006-10-08 11:35:09 · answer #4 · answered by Anonymous · 0 0

I think this question is slightly bogus. It leads you to think about impulse and stuff, but I think the answer is just its weight = m*g.

2006-10-08 11:56:59 · answer #5 · answered by sojsail 7 · 0 0

look up foot pounds pr second in wikipedia- will give you all u need- ain't gunna solve it for u- sorry

2006-10-08 11:48:37 · answer #6 · answered by scootda2nd 2 · 0 0

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