particle has the position ....?

Question

The acceleration of a particle on a horizontal xy plane is given by
a = 3tiˆ + 4tˆj , where a is in metres per second-squared and t is in seconds. At t = 0, the
particle has the position vector r = (20.0 m)iˆ + (40.0 m) ˆj and the velocity vector
v = 5.00 m/s iˆ + 2.00 m/s ˆ r . At t = 4.00 s, what are (a) its position vector in unit-vector
notation and (b) the angle between its direction of travel and the positive direction of the x axis

Answer 1

Apply the one dimesnional position/velocity equations to each of the axis of motion to get the final position/velocity along each axis.

If you don't know what the equations of one dimensional motion are, you need to go back and review them as you obviously screwed off during the first part of your physics class.


Doug