2006-10-08 09:41:14 · 8 answers · asked by kachilous_2002 1 in Science & Mathematics ➔ Mathematics
Wouldn't you need to know the number in the jar before any of them died?
2006-10-08 10:02:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let t be the number of days that have passed since the first day, and d be the number of bugs that have died after t days.
You want a linear model, so d=mt+b, where m and b need to be determined.
13 bugs die per day, so m=13.
40 bugs die the first day, so d=40 when t=0. Therefore, b=40.
It follows that d=13t+40.
2006-10-08 09:44:45 · answer #2 · answered by James L 5 · 0⤊ 0⤋
y= -13x+40
-13x is by how much it dcreases each day and 40 is the satrting point on the y-axis
y-axis= how many bugs have died
x-axis= the days
0- 40
1- 27
2- 14
3- 1
4- -12
it would be something like, assuming there would be 83 in the jar to begin with. i think.
2006-10-08 09:54:36 · answer #3 · answered by Raven 3 · 0⤊ 0⤋
let d equal the day, and b equal the number of bugs that have died.
b = 40 + 13(d-1)
b = 40 + 13d - 13
b = 13d + 27
2006-10-08 09:47:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋
b-40-[x(13)]=0
b equals number of bugs. x is the number of days until all the bugs are gone. hmm...is it even possible 4 that to be linear?
2006-10-08 09:51:48 · answer #5 · answered by calgrlzrockharder 2 · 0⤊ 0⤋
I am not sure but this might be it
you graph the first piont at 40
then you up 13 over 1
i am pretty sure that is how it is done
2006-10-08 09:45:49 · answer #6 · answered by Emily S 1 · 0⤊ 0⤋
i would write this as 40x(40 that die on the first day)times 13y for the bugs that die after every day. so the whole thing looks like this.....
40x+13y
2006-10-08 09:50:40 · answer #7 · answered by hummel kid 3 · 0⤊ 0⤋
x= number of days gone by
y= number of bugs that have died so far
y=13x+40
2006-10-08 09:46:07 · answer #8 · answered by bruinfan 7 · 0⤊ 0⤋