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Question

Simplify: (a^2b)^5c^2 divided by
(ab^2c)^2
Show work

Answer 1

Well Dear ZZ Z;

{ if ;
(a^n)^m = a^(n + m)
(a*b)^n = (a^n) * (b^n)
(a^n) / (a^m) = a^(n - m)
a^-1 = 1/a } ....

(a ² b)^5 c ² / (ab ² c) ² =
[ ( a ^ 2+5)(b ^ 1+5) (c ^ 2)] / [ ( a^1+2)( b^2+2)( c^1+2) ] =
[ (a^7)( b^6)(c^2) ] / [ (a^3) (b^4)( c^3] =
(a^7 / a^3) * ( b^6 / b^4) * ( c^2 / c^3) =
[ (a ^ 7 -3) * ( b^ 6-4) * ( c^ 2-3) ] =
( a^4 ) ( b^2) ( c^-1) =
(a^4) (b^2) (1/c) =
( a^4 b^2) / c

Good Luck dear....

Answer 2

Use these properties of exponents:

(ab)^x = a^x * b^x
(a^x)^y = a^(x*y)
a^x / a^y = a^(x-y)

and you'll be able to simplify it.

Answer 3

maybe you shouldn't have been sleeping in math class. how about using your book or *gasp* looking up how to do it yourself?