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Can anyone help me solve this problem.

The following three statements are TRUE. 23+60=1; 5+5=2 ; and 6+ 24=1.
Explain how this can be.

2006-10-08 09:09:19 · 14 answers · asked by jkelly 2 in Science & Mathematics Mathematics

14 answers

23+60=1 mod 82, 5+5=2 mod 8 6+24=1 mod 29

2006-10-08 09:19:30 · answer #1 · answered by Theodore R 2 · 0 1

a and b are integers such that a=b+1

1. Multiply by (a-b):
(a-b)a=(a-b)(b+1)

2. Distribute:
a^2-ab=ab+a-b^2-b

3. Subtract (a) from both sides:
a^2-ab-a=ab+a-a-b^2-b

4. Factor:
a(a-b-1)=b(a-b-1)

5. Divide by (a-b-1):
a=b

6. Substitute (b+1) for (a):
b+1=b

7. Subtract (b) from both sides:
1=0

8. Multiply by 8:
8=0

9. Add 2:
10=2

10. Rewrite 10 as (5+5)
5+5=2

For other statements change steps 8-10 to read:

a)23+60=1
8. Multiply by 82:
82=0
9. Add 1:
83=1
10. Rewrite
23+60=1

b)6+24=1
8. Multiply by 29
29=0
9. Add 1:
30=1
10. Rewrite:
6+24=1

The error here is in step 5.: Division by (a-b-1)
a-b-1=b+1-b-1=0
Dividing both sides by (a-b-1) led to 0/0, which is undefined.
It is true if you want to divide by 0.

2006-10-08 16:22:24 · answer #2 · answered by mediaptera 4 · 0 1

Hrm. Sounds like math proof to me.

How can they be true? What exactly are you adding?

5 what and 5 what? 5 packages and 5 packages = 2 cases could be a possible explanation.

There is a several hundred page proof simply proving that 1 = 1.

In order to be a proof, there must be unrefutable evidence of exactly what '1' is.

2006-10-08 16:18:21 · answer #3 · answered by p_rutherford2003 5 · 0 1

Using Liberal economic math, this is possible. To the Liberals, 1 million equals 2 billion. The Canadian Liberal party promised the communistic gun registry would only cost 1 million dollars. It cost 2 billion and rising, and it never got fully implemented.

2006-10-08 16:17:43 · answer #4 · answered by Anonymous · 0 1

Are you learning modulo math? If so, then in mod 8 counting, 5+5 = 2.

2006-10-08 16:21:24 · answer #5 · answered by djc 3 · 0 1

One rather sad possibility is that it should read
1 is the number of 'i' s in the numbers sixty and twentythree, it is also the number of 'i's in six and twentyfour but five and five has 2 'i's.

Best of luck - Mike

2006-10-08 16:23:01 · answer #6 · answered by Anonymous · 1 1

In theory they could be true. In the bible time line, or in fractions, or by distribution of ages. The rest, you figure out!! :)
This may also help:
http://www.brentwood.k12.ca.us/brentwood/Curriculum/Math/Math.html

2006-10-08 16:27:08 · answer #7 · answered by Tesra 3 · 0 0

I suggest you start paying attention in class. You're studying modular arithmetic and you're totally lost. Dig out the book and *study* it.


Doug

2006-10-08 16:37:40 · answer #8 · answered by doug_donaghue 7 · 0 1

You had a very bad maths teacher?!

2006-10-08 16:11:03 · answer #9 · answered by Andy C 3 · 0 1

WHAT is this? is ur teacher from and institute or something cause that's not rite!!!

2006-10-08 16:18:23 · answer #10 · answered by Jackie C 1 · 0 1

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