23+60=1 mod 82, 5+5=2 mod 8 6+24=1 mod 29
2006-10-08 09:19:30
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answer #1
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answered by Theodore R 2
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a and b are integers such that a=b+1
1. Multiply by (a-b):
(a-b)a=(a-b)(b+1)
2. Distribute:
a^2-ab=ab+a-b^2-b
3. Subtract (a) from both sides:
a^2-ab-a=ab+a-a-b^2-b
4. Factor:
a(a-b-1)=b(a-b-1)
5. Divide by (a-b-1):
a=b
6. Substitute (b+1) for (a):
b+1=b
7. Subtract (b) from both sides:
1=0
8. Multiply by 8:
8=0
9. Add 2:
10=2
10. Rewrite 10 as (5+5)
5+5=2
For other statements change steps 8-10 to read:
a)23+60=1
8. Multiply by 82:
82=0
9. Add 1:
83=1
10. Rewrite
23+60=1
b)6+24=1
8. Multiply by 29
29=0
9. Add 1:
30=1
10. Rewrite:
6+24=1
The error here is in step 5.: Division by (a-b-1)
a-b-1=b+1-b-1=0
Dividing both sides by (a-b-1) led to 0/0, which is undefined.
It is true if you want to divide by 0.
2006-10-08 16:22:24
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answer #2
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answered by mediaptera 4
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Hrm. Sounds like math proof to me.
How can they be true? What exactly are you adding?
5 what and 5 what? 5 packages and 5 packages = 2 cases could be a possible explanation.
There is a several hundred page proof simply proving that 1 = 1.
In order to be a proof, there must be unrefutable evidence of exactly what '1' is.
2006-10-08 16:18:21
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answer #3
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answered by p_rutherford2003 5
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Using Liberal economic math, this is possible. To the Liberals, 1 million equals 2 billion. The Canadian Liberal party promised the communistic gun registry would only cost 1 million dollars. It cost 2 billion and rising, and it never got fully implemented.
2006-10-08 16:17:43
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answer #4
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answered by Anonymous
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Are you learning modulo math? If so, then in mod 8 counting, 5+5 = 2.
2006-10-08 16:21:24
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answer #5
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answered by djc 3
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One rather sad possibility is that it should read
1 is the number of 'i' s in the numbers sixty and twentythree, it is also the number of 'i's in six and twentyfour but five and five has 2 'i's.
Best of luck - Mike
2006-10-08 16:23:01
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answer #6
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answered by Anonymous
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In theory they could be true. In the bible time line, or in fractions, or by distribution of ages. The rest, you figure out!! :)
This may also help:
http://www.brentwood.k12.ca.us/brentwood/Curriculum/Math/Math.html
2006-10-08 16:27:08
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answer #7
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answered by Tesra 3
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I suggest you start paying attention in class. You're studying modular arithmetic and you're totally lost. Dig out the book and *study* it.
Doug
2006-10-08 16:37:40
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answer #8
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answered by doug_donaghue 7
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You had a very bad maths teacher?!
2006-10-08 16:11:03
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answer #9
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answered by Andy C 3
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WHAT is this? is ur teacher from and institute or something cause that's not rite!!!
2006-10-08 16:18:23
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answer #10
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answered by Jackie C 1
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