factorize 64x^6 - 49y^4?

Answer 1

first we know the rule that : a^2 - b^2 = (a+b) (a-b)

we need to reduce the given expression to this form

we notice that 64 = 8^2; and 49 = 7^2
so the given expression = (8x^3)^2 - (7y^2)^2
it can now be expressed as (8x^3+7y^2) * (8x^3 - 7y^2)

no further simplificatin is possible

Answer 2

this is the form a^2-b^2=(a+b)(a-b)
64x^6 - 49y^4
(8x^3+7y^2)(8x^3-7y^2)

Answer 3

64x^6 - 49y^4

=(8x^3 - 7y^2) (8x^3 + 7y^2)

Answer 4

This is of the form A^2-B^2. This always factors into (A+B)(A-B).

You can check the other way as well.

This is actually a generalization of A^n-B^n=(A-B)(A^(n-1)+A^(n-2)B+...+B^(n-1)).

You can also check that if you want.

Either way, A=8x^3, B=7y^2, so your answer is (8x^3+7y^2)(8x^3-7y^2).

Answer 5

64x^6-49y^4
=(8x^3)^2-(7y^2)^2
=(8x^3+7y^2)(8x^3-7Y^2)