2006-10-08 07:49:13 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well if you substitute 1 into f(x)
it would read f(1) = 3(1)-2 = 1
and if you substitute 0 into g(x)
it would read g(0) = -(0)(2) + 3(0)-2 = -2
Therefore f(1) - g(0) = 1 - (-2) = 1+2 =3
2006-10-08 07:53:23 · answer #1 · answered by michael2003c2003 5 · 0⤊ 0⤋
= 1
2006-10-08 07:56:57 · answer #2 · answered by roger 1 · 0⤊ 1⤋
Evaluate f(x) and g(x) at the indicated points (find f(1) and g(0)), then subtract the value of g from f.
f(1) = 3(1) -2 = 1
g(0) = -(0)^2 + 3(0) - 2 = -2
f(1) - g(0) = 3
(1) - (-2) = 3
2006-10-08 07:52:03 · answer #3 · answered by mrjeffy321 7 · 0⤊ 0⤋
i think the 2d equation ought to examine g(x) = -x^2 + 3x -2. besides, in simple terms plug interior the values of x=a million into f and x=0 into g. We get f(a million) = 3(a million) -2 = 3 - 2 = a million; and g(0) = -(0)^2 + 3(0) -2 = -0 + 0 - 2 = -2. hence, f(a million) - g(0) = a million - (-2) = a million + 2 = 3.
2016-11-27 01:08:06 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Just plug in the numbers:
f(x) = 3x-2
f(1) = 3(1)-2
f(1)=1
Same for g(x) for g(0). You'll get -2
Then, 1-(-2) = 3.
2006-10-08 07:52:55 · answer #5 · answered by mysstere 5 · 0⤊ 0⤋
[3(1)-2] - [-0(2)+3(0)-2]
=[3-2] - [-0+0-2] Note- Zeros are neutral nubers
=1-(-2)
=1+2
=3
2006-10-08 07:57:44 · answer #6 · answered by Dex's Gal 3 · 0⤊ 0⤋
Would the answer be 1?
2006-10-08 07:51:40 · answer #7 · answered by Anonymous · 0⤊ 1⤋