a. the same
b. less in water
c. twice as much in water
d. none of the above
2006-10-08 06:25:43 · 7 answers · asked by Joan S 1 in Science & Mathematics ➔ Earth Sciences & Geology
The weight will be less in water. so the ANSWER IS 'b'.
Reason: When we weight in air the only force acting is the gravitational force which acts downwards side while, in water two kind of force are actin on the body, the one is gravtational force which is actin downwards side and the other is byouant force which acts in opposite direction than gravitational force, because of this the weight of body seems to be lighter in water than in air.
2006-10-08 06:37:09 · answer #1 · answered by smilingbook1 2 · 0⤊ 0⤋
Depends on the type of rock and the amount of trapped gasses inside. The mass of a rock never changes as long as it doesn't physically change but the weight of a rock can be affected by buoyancy in different environments.
You don't necessarily need to put a rock in water to assess its buoyancy though... A rock filled with helium bubbles would weigh slightly more in outer space than it does in the Earth's atmosphere at sea level because air is more dense than helium.
Never think though that since rocks fall to the ground slower in water than in air that their weight has somehow been reduced... rocks fall slower underwater because there are more molecules of substance per unit-volume to move out of the way for the rock to pass through liquid than it has to move out of the way while passing through a gas.
2006-10-08 14:17:38 · answer #2 · answered by wreck_beach 4 · 0⤊ 0⤋
Answer is B
Archimedes' principle states that the buoyant force experienced by a submerged object is equal to the weight of the liquid displaced by the object. Experimentally this appears in the fact that the submerged object apparently weighs less by an amount equal to the weight of the liquid displaced.
2006-10-08 15:18:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The rock's weight has to be constant even though there might be exterior influences reducing it's apparent weight.
Unless you move your test to a completely different gravity field, the right answer is A.
2006-10-08 13:33:09 · answer #4 · answered by juliepelletier 7 · 0⤊ 0⤋
the weight should remain the same but the density is different. or something like that
2006-10-08 13:35:41 · answer #5 · answered by pmktabbycat 3 · 0⤊ 0⤋
THink!!!!
B
Haven't you ever picked something up in water? Like picking up someone in a pool?
2006-10-08 13:26:47 · answer #6 · answered by Anonymous · 0⤊ 0⤋
don't know
2006-10-08 13:27:07 · answer #7 · answered by David T 2 · 0⤊ 0⤋