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How would u solve for this.

2006-10-08 04:44:35 · 6 answers · asked by DaOne 1 in Science & Mathematics Mathematics

6 answers

You can convert any number to any base by dividing the number repeatedly by the base and writing down the remainder. For example, convert 4723 to base 4. I just divide by 4 over and over and the remainders are the digits in the the base 4 number:

4723 / 4 = 1180 with remainder 3 so 3 is the last digit of the number and I need to divide the 1180 by 4 and so on

1180 / 4 = 295 Remainder 0
295 / 4 = 73 Remainder 3
73 / 4 = 18 Remainder 1
18 / 4 = 4 Remainder 2
2 / 4 = 0 Remainder 2

Now write down all the remainders in reverse order:

221303 is the number 4723 converted to base 4. Try this on your number.

2006-10-08 05:03:38 · answer #1 · answered by Pretzels 5 · 1 1

a million. An set of rules to transform to base 2 is to persistently divide the extensive style by making use of two till you get to 0 and checklist the remainders. The series backwards is the extensive style in base 2. ninety seven/2 = 40 8 R a million 40 8/2 = 24 R 0 24 /2 = 12 R 0 12 /2 = 6 R 0 6/2 = 3 R 0 3/2 = a million R a million a million/2 = 0 R a million So ninety seven in base 2 is 1100001.

2016-10-19 00:46:27 · answer #2 · answered by Anonymous · 0 0

10121
1*81+1*9+2*3+1=81+9+6+1=97

2006-10-11 16:11:16 · answer #3 · answered by yupchagee 7 · 0 0

10121
3^0=1; 3^1=3; 3^2=9; 3^3=27; 3^4=81
97-81=16 - Put a one in highest place.
16-27 - negative number - put zero in next place
16-9=7 - put a one in next place
7-3=4; 4-3=1 - put a two on next place
1-1=0 put a one in last place

2006-10-08 04:52:41 · answer #4 · answered by Amphibolite 7 · 0 0

Pretzel's answer is the exact method for finding the number in a different base. Excellent answer.

2006-10-08 05:16:00 · answer #5 · answered by kevvsworld 3 · 0 1

answer is 3121.
97/3 quo=32 ,rem = 1
32/3 quo=10 ,rem = 2
10/3 quo=3 ,rem = 1 n stop (3/3 quo = 1 ,rem = 0)

write the nos in reverse i.e 3121

2006-10-08 05:05:57 · answer #6 · answered by varun 1 · 0 1

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