2006-10-08 03:48:35 · 15 answers · asked by Anonymous in Sports ➔ Auto Racing
Probably J.J. Yeley. He wrecks every car he drives.
But, on the bright side I hope Jr. wins! :-)
2006-10-08 04:02:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Now one is probably going to make a big one in Talladega because they put new smooth cement because the other cement was bumpy that's why there was allot of wrecks in my opinion.
2006-10-08 12:25:13 · answer #2 · answered by ktpotaty@verizon.net 2 · 0⤊ 0⤋
I gotta agree with D jr. fan, that is of course there isnt a Bodine in the race! LOL! Uh oh, Tods in there! Lookout! The stupidest of the Bodines! Lets not forget Derrick " The Dork" Cope either!
2006-10-08 13:42:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Im betting that there wont be one at all. The new paved track is so smooth its going to make for one heck of a race, with no major cautions! If it does happen it will be because some inexpierinced rookie to impatient to listen to the advice of the veterens.
2006-10-08 16:20:13 · answer #4 · answered by firedup 6 · 0⤊ 0⤋
Tony Stewart
2006-10-08 12:23:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋
David Gillilland. He's gonna think he's something after getting the pole and try driving beyond his ability. He already wrecks every car he gets in and now he's on pole!
I'm rooting for Jimmie...he deserves a championship after running 1st through the majority of the past 3 seasons.
2006-10-08 10:58:42 · answer #6 · answered by windfall187 2 · 0⤊ 1⤋
Probably Jeffy Poopoo!
2006-10-08 12:39:37 · answer #7 · answered by LadyL 4 · 0⤊ 0⤋
I's have to agree with windfall and say David Gillilland for the same reasons she stated.
Go Jr!!!!! #8
2006-10-08 12:05:39 · answer #8 · answered by Luke J 2 · 0⤊ 0⤋
a couple of drivers come to mind R Gordon or one of the Busch boys
2006-10-08 13:46:51 · answer #9 · answered by nas88car300 7 · 0⤊ 0⤋
Robby Gordon will. He's a retard and he will be over-confident with his car because of the new surface.
2006-10-08 14:22:42 · answer #10 · answered by Katie 2 · 0⤊ 0⤋