The sphere would have to be constructed from diamond film or some other ultra light super strong material, C60 sheet for example, to withstand the air pressure.
2006-10-08 01:45:28 · 9 answers · asked by shardfang40k 1 in Science & Mathematics ➔ Physics
no becauseit has to have either a very strong or a very weak gravitational pull for it to rise into orbit but for it to rise, its density would have to be that of equal or less than hydrogen which is vey hard to accomplish
2006-10-08 01:51:54 · answer #1 · answered by hendrix fan 54 2 · 0⤊ 1⤋
Technically, no. There are two scenarios:
1. The sphere is massless (or at least low enough mass to achieve escape velocity as it rises past the outer atmosphere). It will then leave the earth and not achieve orbit.
2. The sphere has mass and remains within the atmosphere to provide buoyancy. In this case, by definition, it is not in orbit. There is no way for the sphere to achieve the lateral velocity needed to maintain orbital conditions. Even if it rises out of the atmosphere, it will fall back (maybe skip a few times) and remain as a buoyant object within the upper atmosphere.
Of course, if one considers a hot air balloon as being in orbit, then the sphere will also be in orbit.
2006-10-08 06:38:33 · answer #2 · answered by or_try_this 3 · 0⤊ 0⤋
It would rise like a weather balloon to an altitude where the air density is such that the sphere's volume times the air density (in other words, the sphere's buoyancy) equals its weight. However the sphere wouldn't orbit unless you gave it the necessary velocity (roughly 5 mi/sec). You would have to do an analysis with the actual weight and construction material to find out whether friction of the rarified air at this velocity would cause the sphere to burn up or weaken.
2006-10-08 02:02:58 · answer #3 · answered by kirchwey 7 · 1⤊ 0⤋
your sphere would rise only if your super strong material weighed less than the amount of air that it and the vacuum contained in it displaced.
and then it would only rise to a point where it's weight equaled the weight of the air at the altitude that it is now at. The atmosphere get less dense as you go up.
your super strong sphere would never leave the atmospher unless it weighed nothing!
let me know how you get on!
2006-10-08 02:01:30 · answer #4 · answered by Me 3 · 1⤊ 0⤋
Quite simply -No.
Don't get this mixed up with bouyancy. If the sphere is completely sealed and vacated, the atmospheric pressure is the same from all directions. It's going nowhere.
2006-10-08 03:33:52 · answer #5 · answered by Bill N 3 · 0⤊ 0⤋
ya it will rise if the weight of the sphere is less than the amount of air it displaces at that particular height, when air's density falls to a point when the weight of the amount of displaced air equals the weight of sphere it will stop rising..
2006-10-08 02:26:43 · answer #6 · answered by DaKeiko 2 · 0⤊ 0⤋
calc the average density of your sphere
it will rise till that density is equal to the air density
you would get better results if you were to make it out of something that had negative mass.
2006-10-08 01:55:21 · answer #7 · answered by Anonymous · 1⤊ 0⤋
No. no matter what you put in it i would always be heavier than a vacuum so it would stop at some stage in the atmosphere. It needs to reach escape velocity....see here.
2006-10-08 01:56:15 · answer #8 · answered by Anonymous · 1⤊ 0⤋
theoriticaly yes
2006-10-08 01:53:29 · answer #9 · answered by soumyaxyz 2 · 0⤊ 0⤋