2006-10-07 20:40:34 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There are 38880 different ways to put those in different order, not counting 0 in the first position.
2006-10-07 20:49:50 · answer #1 · answered by Custo Dian 3 · 0⤊ 0⤋
we can make numbers of 5,6 digits
for 5 digit nos first digit is 0
_ _ _ _ _ _
first blank is filled by 0(1 way) & other 5 blanks filled in 5! ways
total we get 1* 5! ways
for 6 digit nos first digit can be filled by nos except 0 i.e, 1,2,7,8,4
_ _ _ _ _ _
fist blank is filled by anyone of 5nos in 5ways & next five blanks are filled by the other digits except the no used for first blank along with 0 i.e, in 5! ways
total we get 5*5! ways
hence total nos we get by given nos are 1*5!+5*5! = 6*5!
2006-10-07 22:37:25 · answer #2 · answered by . 3 · 0⤊ 0⤋
6!=720
2006-10-07 20:51:16 · answer #3 · answered by sandee 2 · 0⤊ 0⤋
If by just arranging the numbers...
you can get
5*(5!) =5*(120)=600
600 numbers.
2006-10-07 20:49:24 · answer #4 · answered by CaiZ.StarGazer 2 · 0⤊ 0⤋
5*5! = 600
the first digit cannot be 0 --
hope this helps
2006-10-07 21:11:41 · answer #5 · answered by ilovemath_pi 2 · 0⤊ 0⤋
Using addition only, you can count up to 22
2006-10-07 20:44:17 · answer #6 · answered by arbiter007 6 · 0⤊ 0⤋
Using all of them
600
2006-10-07 20:47:46 · answer #7 · answered by ag_iitkgp 7 · 0⤊ 0⤋
5*6*6*6*6*6=38880
2006-10-07 21:09:02 · answer #8 · answered by iluvpepsi 1 · 0⤊ 0⤋