How long, in seconds, does it take an automobile traveling 50.0 km/h to become even with a car that is traveling in another lane at 40.0 km/h if the cars' front bumpers are initially 122 m apart?
2006-10-07 19:33:43 · 3 answers · asked by Fanjame 1 in Science & Mathematics ➔ Mathematics
50-40 = 10 km/hr
122 m(60 min/hr)(60 sec/min)/((1000m/ km)(10 km/hr)) =
2006-10-07 22:25:31 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
Relative to the slower car, the faster car is going 10 km/h
distance = veloctity * time
122 = 10 * time
Time = 12.2 seconds
2006-10-08 02:37:35 · answer #2 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
The closing velocity is just the difference between the two. Distance = velocity * time. so time = distance/velocity. You have the distance, and you have the velocity difference. Solve it.
2006-10-08 02:37:12 · answer #3 · answered by gp4rts 7 · 0⤊ 0⤋