when a fifty-cent coin at the temperature of 25 degree celcius is dropped into a beaker of water at 90 degree celcius, what will happen to the temperature of both the water and the coin? explain why.
2006-10-07 18:44:30 · 6 answers · asked by pufferfish 1 in Education & Reference ➔ Primary & Secondary Education
The temperature of the coin will increase and the temperature of the water will decrease (depending on how much water is in the beaker) until they reach equilibrium. The coin will conduct the heat, reducing the temperature of the surrounding water.
2006-10-07 18:49:38 · answer #1 · answered by Sheila 3 · 0⤊ 0⤋
The temperature of the coin with increase and the temperature of the water will decrease. This will happen until the coin and the water are the same temperature.
There is an equation to determine what the final temperature of both will be but you would need to know how much water there is.
Heat always flows from hot to cold.
2006-10-08 03:04:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I second everything that Sheila said! The object would absorb some of the heat and cool the water. The more important question is this: are you posting your homework questions? Tsk tsk tsk!
2006-10-08 01:54:35 · answer #3 · answered by thyladydulcinea 2 · 0⤊ 0⤋
temperature of coin will rise and temperature of water will fall
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2006-10-08 11:03:40 · answer #4 · answered by Rachit Sood 2 · 0⤊ 0⤋
http://matrixexplained.ytmnd.com/
2006-10-08 01:45:28 · answer #5 · answered by Mr.Quads 2 · 0⤊ 1⤋
SHIELA IS RIGHT
2006-10-08 01:53:56 · answer #6 · answered by RAMAN IOBIAN 7 · 0⤊ 0⤋