I'm currently studying quadratic equations in the form ax^2+bx+c=0. If you can, post a problem or two that I can solve. Don't post the answer, cause I'll cheat, probably :). I'll send a message to an individual user if I need any help. Make sure that the problem is difficultl, yet factorable; I haven't learned the quadratic formula yet.Thank you for the help!
2006-10-07 17:31:36 · 6 answers · asked by perriermb 1 in Education & Reference ➔ Homework Help
Sure. Here are a few:
7x² + 18x + 8
4x² - 12x + 8
2x² + x - 3
4x² + 10x + 6
If you need any help, you're going to have to send some work along, too. My e-mail is katiecole91@yahoo.com. I'm not just sending answers so you can "cheat" as you stated in the question.
2006-10-09 08:28:10 · answer #1 · answered by katiecole91 2 · 0⤊ 0⤋
Here's a few. =) Pick however many you want:
4x^2 + 14x + 6 = 0
2x^2 - x - 3 = 0
-6x^2 + 27x + 15 = 0
3x^2 - 2x - 5 = 0
2006-10-07 17:40:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
determine whether the given quadratic equation has root(s).If so find the root(s).
1/x+1 +2/x+2 =4/x+4
(x is not equal to -1,-2,-4)
2006-10-07 17:44:59 · answer #3 · answered by SRI L 1 · 0⤊ 0⤋
x^2+4 59948 11347 64527 31678 28101 22164 60768 62790x-1 11111 11111 11111 11111 11111 11111 11111 11111 11111 11111 11111 11111 11111 11111 = 0
This difficult enough for you? (Yes, this problem IS factorable).
2006-10-07 17:43:40 · answer #4 · answered by Pascal 7 · 0⤊ 0⤋
4X^2 + 0X - 16 = 0
this should be managable !
2006-10-07 17:40:48 · answer #5 · answered by vlmt 1 · 0⤊ 0⤋
1)3x^2+11x-4=0
2)3x^2-5x-1=0
Hope these were helpful
2006-10-07 17:40:13 · answer #6 · answered by shynryd 2 · 0⤊ 0⤋