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The diagram below shows a block of mass m=2.0\; \rm kg on a frictionless horizontal surface, as seen from above. Three forces of magnitudes F_1 = 4.0\;{\rm N}, F_2 = 6.0\;{\rm N}, and F_3 = 8.0\;{\rm N} are applied to the block, initially at rest on the surface, at angles shown on the diagram. View Figure In this problem, you will determine the resultant (total) force vector from the combination of the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive).

Calculate the magnitude of the total resultant force \vec{F}_{\rm r} = \vec{F}_1+ \vec{F}_2 +\vec{F}_3 acting on the mass.

2006-10-07 17:19:50 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Your diagrams didn't show up in your question, but basically this is a very simple problem to solve:

(1) Take each Force acting on the mass and divide them into X-component's, and Y-component's (note: there should be NO Z-component forces, since this problem is dealing with a frictionless horizontal surface)

(2) Add up the X-component forces, and then add up the Y-component forces (note: make sure that you subtract component forces that are in the opposite direction from the X or Y positive directions.)

(3) To calculate the magnitude of the resultant force, use the following formula:

F(net) = sqrt(F(x-net)^2+F(y-net)^2)

2006-10-07 18:00:32 · answer #1 · answered by PhysicsDude 7 · 0 0

Your angles did not show up.

2006-10-07 17:34:57 · answer #2 · answered by Helmut 7 · 0 0

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