A ball of diameter 31cm rolls without slipping at a linear speed of 2.8 m/s. Through how many revolutions has the ball turned as it moves a linear distance of 18 m?
Okay, how do i set this up to solve it?
I am thinking that I just take the distance and divide by the speed, and I correct in thinking this? 18m/2.8?
2006-10-07 13:36:37 · 4 answers · asked by Trevor M 1 in Science & Mathematics ➔ Physics
so using what you said i would have 2pi X 15.5 divided by 9.74 which would give me 1.85 m?
2006-10-07 14:10:17 · update #1
Dividing the distance traveled by the linear speed will only give you the time it takes for the ball to roll this far, but you are looking for the number of revolutions the ball takes over this distance.
You are given the diameter of the ball, from this you can find the circumference of the ball (c = 2*pi*r).
For every 1 revolution of the ball it travels a linear distance equal to its circumference (since the ball does not slip). So dividing the linear distance traveled by the ball's circumference will give you the number of time the ball makes a complete revolution along its path.
For this question the time given is irrelevant, it only becomes useful when you want to find the angular speed of the ball (radians per second, or possibly RPM).
EDIT:
The linear distance traveled is given as 18 meters. The Diameter is 31 centimeters, but first you need to convert this into meters (31 cm = .31 m). To find the circumference multiply the diameter by pi (.31 meters * pi). Now divide the linear distance traveled by the circumference per revolution of the ball. Your final answer should be in units of revolutions, not meters.
meter / meters per revolution = revolutions
2006-10-07 13:44:45 · answer #1 · answered by mrjeffy321 7 · 0⤊ 0⤋
Hi. The diameter is 31cm, not the circumference. The 18m has to be divided by 31cm x pi. Holden is right. The 2.8m is a distraction.
2006-10-07 15:52:46 · answer #2 · answered by Cirric 7 · 0⤊ 0⤋
The ball rolls one circumference per revolution.
What is the circumference of the ball? 31cm x pi
how many circumferences are there in 18M?
the 2.8 m/s is obfuscation.
2006-10-07 13:40:57 · answer #3 · answered by Holden 5 · 0⤊ 0⤋
confident, in a uniform around action there's a uniform acceleration, this is radial, pointing to the centre of the circle. In a around action there is not '0 velocity' as you stated, by way of fact if so the physique could fall to the centre. Uniform around motions are the manufactured from 2 issues: a effective rigidity, that creates the radial acceleration, and a tangent velocity, so as that the physique won't in simple terms in simple terms fall yet as a replace flow alongside a around course.
2016-11-26 23:50:04 · answer #4 · answered by moodey 4 · 0⤊ 0⤋